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Alexus [3.1K]
4 years ago
8

Given: Tangents LA and LB m∠AOB=110° Find: m∠ALO.

Mathematics
1 answer:
Ad libitum [116K]4 years ago
7 0

Answer:

35°

Step-by-step explanation:

From any point outside a circle, the two tangents to that circle are always congruent to each other. This can be proven by taking the two triangles ΔLAO and ΔLBO and prove that they are congruent. From the upper triangle AO is congruent to BO because AO = BO = Radius. Also, LO is the same length for both triangles, therefore two equal sides. Moreover, the measure of an angle between the tangent to a point of the circle and the radius going from the center to that point equals 90°, so ∠LAO = ∠LBO = 90°. So these two triangles ΔLAO and ΔLBO are congruent by SSA postulate.

If m∠AOB=110°, then m∠AOL = 110°/2 =55°. Finally, the angles of every triangle always measures 180°, therefore:

m∠ALO = 180°-55°-90 = 35°

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Step-by-step explanation:

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3 years ago
Two ships leave the same port at the same time. Two hours later ship A has traveled 12 miles and ship B has traveled 8 miles.
sashaice [31]

Answer:

the angle between their paths is <em>100.8°</em>

Step-by-step explanation:

From the given information, you can construct a triangle, just like the one in the figure.

We will use the <em>Cosine Rule</em> which is:

c² = b² + a² - 2 b c cos(θ)

where

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Therefore,

2 b c cos(θ) = b² + a² - c²

cos(θ) = (b² + a² - c²) / 2 b c

θ = cos⁻¹( (b² + a² - c²) / (2 b c) )

θ = cos⁻¹( (8² + 12² - 16²) / 2(8)(16) )

<em>θ = 100.8°</em>

<em></em>

Therefore, the angle between their paths is <em>100.8°</em>

4 0
3 years ago
Solve the following system to find the point(s) of intersection. <br> y = x² - 2x - 3<br> y = 2x - 3
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5 0
2 years ago
The coordinates of LMN are L (4,5), M (5,-2), and N (0,0). If the triangle is rotated 270° about point N, what are the coordinat
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If the triangle is rotated 270° about point N

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(5,-2)\to (-2,-5)   (Using the rule described in (1))

Hence, the coordinates of M after rotated 270° about point N=(-2,-5).

8 0
4 years ago
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3 years ago
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