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Flura [38]
2 years ago
9

The swallowtail caterpillar is an example of a ?

Chemistry
1 answer:
tresset_1 [31]2 years ago
8 0

Answer:

B)  Consumer COnsumer COnsumer

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What is the mass of a sample containing 3.5 moles of silicon atoms?
Natalija [7]
The answer is c .”98 g “
3 0
2 years ago
The addition of 250.0 J to 30.0 g of copper initially at 22.0°C will change its temperature to what final value? (Specific heat
WINSTONCH [101]

Answer:

Final temperature = 43.53^{\circ} C

Explanation:

Given that,

Heat added, Q = 250 J

Mass, m = 30 g

Initial temperature, T₁ = 22°C

The Specific heat of Cu= 0.387 J/g °C

We know that, heat added due to the change in temperature is given by :

Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1

Put all the values,

T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C

So, the final temperature is equal to 43.53^{\circ} C.

8 0
3 years ago
Scientist who discovered the atomic nucleus is ________. dalton b. thomson chadwick d. rutherford
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It’s D. Rutherford discovered the atomic nucleus.
7 0
3 years ago
Calculate the heat change involved when 2.00 L of water is heated from 20.0/C to 99.7/C in
Pani-rosa [81]

Answer:

666,480 Joules or 669.48 kJ

Explanation:

We are given;

  • Volume of water as 2.0L or 2000 ml

but, density of water is 1 g/ml

  • Therefore, mass of water is 2000 g
  • Initial temperature as 20 °C
  • Final temperature as 99.7° C

Required to determine the heat change

We know that ;

Heat change = Mass × Temperature change × specific heat

In this case;

Specific heat of water is 4.2 J/g°C

Temperature change is 79.7 °C

Therefore;

Heat change = 2000 g × 79.7 °C × 4.2 J/g°C

                      = 669,480 Joules 0r 669.48 kJ

Thus, the heat change involved is 666,480 Joules or 669.48 kJ

5 0
3 years ago
Atomic mass protons column electrons atomic number neutrons row 11 12 23
zysi [14]
A) Mass Number B) Protons and Electrons C) (I think group but I'm not 100% sure on this...) D) 12 (To work out the number of neutrons you do MASS number - ATOMIC number aka the number of protons so in this case you'd do 23-11=12) Hope this helps
3 0
3 years ago
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