This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:
Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻ ⇒2K⁺O⁻²H⁺ + I₂⁰
Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻
Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.
In such a way, the correct choice is C.
Learn more:
It allows electrons to flow from the anode to the cathode.
86 elections so 43 orbitals
Answer:
1.52 L
Explanation:
P1V1T2=V2P2T1
V2=V1T2/T1
Fill in with given values then solve
We can check this by knowing that V and T at constant P have a proportional relationship. Hence, this is correct.
- Hope that helped! Please let me know if you need further explanation.
