Answer:
(f- g)(x) = x - 3
Step-by-step explanation:
(f- g)(x) = f(x) - g(x)
This means that you have to subtract the two equation.
If f(x) = 3x - 2 and g(x) = 2x + 1
Then
f(x) - g(x) = [3x - 2] - [2x+1]
= 3x - 2- 2x - 1
= x - 3
∴ (f- g)(x) = x - 3
Let x is the odd integer
x +2 is the next odd integer
so sum of an odd integer and the next odd integer:
x + (x+2)
The logarithm of a quotient can be written as a difference of logarithms:

You can also think of this as a combination of the product-to-sum and reciprocal/power properties of logarithms:

To summarize,


