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hodyreva [135]
2 years ago
11

19 + 8j = 75 j = ____

Mathematics
2 answers:
jarptica [38.1K]2 years ago
7 0

Answer:

j=57/8

Step-by-step explanation:

Taya2010 [7]2 years ago
4 0

Answer:

J=7

Step-by-step explanation:

calculate

8j=75-19,

Divide both sides

8j=56

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The circumference of a circle is 15π ft. What is the area, in square feet? Express your answer in terms of π.
DerKrebs [107]

Answer:

  • Area of the circle is 56.25π square feet.

Step-by-step explanation:

<u>Given that</u>:

  • The circumference of a circle is 15π ft.

<u>To Find</u>:

  • What is the area, in square feet?

<u>We know that</u>:

  • Circumference of a circle = 2πR
  • Area of a circle = πR²

Where,

  • Radius is denoted as R.

<u>Finding the radius of the circle</u>:

Circumference of a circle = 15π

⟶ 2πR = 15π

⟶ 2πR = 2π × 7.5

Cancelling 2π.

⟶ R = 7.5

∴ Radius of the circle = 7.5 ft.

<u>Finding the area of the circle</u>:

⟶ Area = πR²

⟶ Area = π(7.5)²

⟶ Area = π × 7.5 × 7.5

⟶ Area = π × 56.25

⟶ Area = 56.25π

∴ Area of the circle = 56.25π ft.²

7 0
3 years ago
What is 67 x 578 divide by 5?
MA_775_DIABLO [31]

Answer:

7745.2

Step-by-step explanation:

you need to multiply 67 by 578 which is 38726. then you divide it by 5. In short, you can just use calculator or you can use scratch paper.\

3 0
3 years ago
Read 2 more answers
Which of the following means the same as 2(3x – 4) ?
Lorico [155]

Answer:

6x - 8

Step-by-step explanation:

2(3x – 4)

Distribute

2*3x - 2*4

6x - 8

8 0
3 years ago
Write the standard form of the line that passes through the point (1,5) and is parallel to the x -axis. Include your work in you
scoray [572]

Answer:

y = 5

Step-by-step explanation:

A line parallel to the x- axis has equation

y = c

Where c is the value of the y- coordinates the line passes through

The line passes through (1, 5) with y- coordinate of 5, thus

y = 5 ← equation of line

7 0
3 years ago
Find the solutions of the quadratic equation 14x^2+9x+10=014x
Vesnalui [34]

Answer:

Option B. x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

14x^{2}+9x+10=0

so

a=14\\b=9\\c=10

substitute in the formula

x=\frac{-9(+/-)\sqrt{9^{2}-4(14)(10)}} {2(14)}

x=\frac{-9(+/-)\sqrt{-479}} {28}

Remember that

i=\sqrt{-1}

substitute

x=\frac{-9(+/-)\sqrt{479}i} {28}  

x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

5 0
3 years ago
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