Answer:

Explanation:
To solve this exercise it is necessary to take into account the concepts related to gravitational potential energy, as well as the concept of perigee and apogee of a celestial body.
By conservation of energy we know that,

Where,

Replacing


Our values are given by,





Replacing at the equation,


Therefore the Energy necessary for Sputnik I as it moved from apogee to perigee was 
yes. gravity is working on you and everything on you.
also earth is rotating
no not in respect ofimmediate surroundings
object could move at constant velocity = no change in either magnitude or direction
change of position "proves" this
Answer:
9.8 × 10⁴Pa
Explanation:
Given:
Velocity V₁ = 12m/s
Pressure P₁ = 3 × 10⁴ Pa
From continuity equation we have
ρA₁V₁ = ρA₂V₂
A₁V₁ = A₂V₂
making V₂ the subject of the equation;

the pipe is widened to twice its original radius,
r₂ = 2r₁
then the cross-sectional area A₂ = 4A₁
⇒ 

This implies that the water speed will drop by a factor of
because of the increase the pipe cross-sectional area.
The Bernoulli Equation;
Energy per unit volume before = Energy per unit volume after
p₁ +
ρV₁² + ρgh₁ = p₂ +
ρV₂² + ρgh₂
Total pressure is constant and
= P =
ρV₂²ρV²
p₁ +
ρV₁² = p₂ +
ρV₂²
Making p₂ the subject of the equation above;
p₂ = p₁ +
ρV₁² -
ρV₂²
But
so,
p₂ = p₁ +
ρV₁² -
ρ
p₂ = 3.0 x 10⁴ + (
× 1000 × 12²) - (
× 1000 × 12²/4² )
P₂ = 3.0 x 10⁴ + 7.2 × 10⁴ - 4.05 x 10³
P₂ = 9.79 × 10⁴Pa
P₂ = 9.8 × 10⁴Pa