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Serga [27]
3 years ago
8

According to ohms law, as the voltage increases across a 40 ohm resistor what happens to the current, resistors, and resistance

Physics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

As the voltage increases, the current flowing through the circuit increases while the resistance of the resistor remains constant.

Explanation:

Ohm's law states that the current flowing through a circuit is directly proportional to the applied voltage.

V = IR

where;

I is the current

R is the resistance

V is the applied voltage

Based on this law (Ohm's law), as the voltage increases, the current flowing through the circuit increases while the resistance of the resistor remains constant.

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5 0
4 years ago
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A 68.5kg astronaut floating motionless next to the space station throws a 2.25kg tool away from her at 3.20m/s. With what speed
valkas [14]

Answer:

-0.105 m/s

Explanation:

Given that

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5 0
4 years ago
The burner on an electric stove has a power output of 2.0 kW. A 710 g stainless steel tea kettle is filled with 20∘C water and p
asambeis [7]

Answer:

The volume of water that was in the kettle is  1170 cm^{3}

Explanation:

Given:

Power, P = 2.0 kW = 2000 W, Mass of stainless steel, m_{s} = 710 g = 0.71 kg at temperature of  20^{0} C

Part A:

If it takes time, t = 3.5 minutes to reach boiling point of water 100^{0} C, then from conservation of energy,

Total energy supplied by the burner = Total heat gained by the water and the stainless steel to rise from 20^{0} C to 100^{0} C

i.e. Pt = m_{s}c_{s}(100 - 20 ) + m_{w}c_{w}(100 - 20 )

m_{w} = \frac{pt - 80m_{s} C_{s} }{80c_{w} } = \frac{2000*3.5*60 - 80*0.71* 450}{80*4200}

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But volume of water in the the kettle, v = \frac{mass}{density} = \frac{1.17}{1000}= 1.17 *10^{-3} m^{3}

∴ v = 1170 cm^{3}

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4 years ago
Eq-36 when paddling a canoe at night, which piece of equipment should be carried to help avoid a collision?
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