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Serga [27]
3 years ago
8

According to ohms law, as the voltage increases across a 40 ohm resistor what happens to the current, resistors, and resistance

Physics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

As the voltage increases, the current flowing through the circuit increases while the resistance of the resistor remains constant.

Explanation:

Ohm's law states that the current flowing through a circuit is directly proportional to the applied voltage.

V = IR

where;

I is the current

R is the resistance

V is the applied voltage

Based on this law (Ohm's law), as the voltage increases, the current flowing through the circuit increases while the resistance of the resistor remains constant.

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The first artificial satellite to orbit the Earth was Sputnik I, launched October 4, 1957. The mass of Sputnik I was 83.5 kg, an
9966 [12]

Answer:

-4.941*10^8J.

Explanation:

To solve this exercise it is necessary to take into account the concepts related to gravitational potential energy, as well as the concept of perigee and apogee of a celestial body.

By conservation of energy we know that,

\Delta U = \Delta_{perogee}-\Delta_{Apogee}

Where,

U= \frac{-GmM_e}{r}

Replacing

\Delta U = \frac{-GmM_e}{r_p}- \frac{-GmM_e}{r_a}

\Delta U = GmM_e (\frac{1}{r_A}-\frac{1}{r_p})

Our values are given by,

m = 85.5Kg

M_e = 5.97*10^{24}Kg

r_A = 7330Km

r_p = 6610Km

G = 6.67*10^{-11}Nm^2/Kg^2

Replacing at the equation,

\Delta U = (6.67*10^{-11})(85.5)(5.97*10^{24}) (\frac{1}{7330}-\frac{1}{6610})

\Delta U = -4.941*10^8J

Therefore the Energy necessary for Sputnik I as it moved from apogee to perigee was -4.941*10^8J.

4 0
3 years ago
a car is traveling at velocity of 15m/s.it accelerates to a velocity 35m/s in 10s calculate the acceleration? ​
vlada-n [284]

Answer:

2m/s is acceleration I hope it helps you

3 0
2 years ago
Read 2 more answers
1.) if you are sitting still are you accelerating? How do you know?
castortr0y [4]

yes. gravity is working on you and everything on you.

also earth is rotating


no not in respect ofimmediate surroundings

object could move at constant velocity = no change in either magnitude or direction

change of position "proves" this

5 0
3 years ago
Water, which we can treat as ideal and incompressible, flows at 12 m/s in a horizontal pipe with a pressure of 3.0 × 10^4 Pa.
Triss [41]

Answer:

9.8 × 10⁴Pa

Explanation:

Given:

Velocity V₁ = 12m/s

Pressure P₁ = 3 × 10⁴ Pa

From continuity equation we have

                              ρA₁V₁ = ρA₂V₂

                                 A₁V₁ = A₂V₂

making V₂ the subject of the equation;

                               V_{2} = \frac{A_{1}V_{1}}{A_{2}}

the pipe is widened to twice its original radius,

                                r₂ = 2r₁          

then the cross-sectional area A₂ = 4A₁

                           ⇒  V_{2}= \frac{A_{1}V_{1}}{4A_{1}}

                                  V_{2}= \frac{V_{1}}{4}

This implies that the water speed will drop by a factor of  \frac{1}{4} because of the increase the pipe cross-sectional area.  

 The Bernoulli Equation;

     Energy per unit volume before = Energy per unit volume after    

        p₁ + \frac{1}{2}ρV₁²  + ρgh₁ = p₂ + \frac{1}{2}ρV₂²  + ρgh₂  

Total pressure is constant and P_{T} = P = \frac{1}{2}ρV₂²ρV²  

        p₁ + \frac{1}{2}ρV₁²  = p₂ + \frac{1}{2}ρV₂²

Making p₂ the subject of the equation above;

        p₂ = p₁ + \frac{1}{2}ρV₁² - \frac{1}{2}ρV₂²

But V_{2}  = \frac{V_{1}}{4} so,

        p₂ = p₁ + \frac{1}{2}ρV₁² - \frac{1}{2}ρ\frac{V_{1}^{2}}{4^{2}}      

       p₂ = 3.0 x 10⁴ + (\frac{1}{2} × 1000 × 12²) - ( \frac{1}{2} × 1000 × 12²/4² )

      P₂ = 3.0 x 10⁴ + 7.2 × 10⁴ - 4.05 x 10³    

       P₂ = 9.79 × 10⁴Pa      

      P₂ = 9.8 × 10⁴Pa                      

4 0
2 years ago
A car travels at a velocity of 8m/s for 16s . How far did it travel?
sertanlavr [38]

Answer:128m

Explanation:

8*16=128

7 0
3 years ago
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