2 years ago

The surface tension of isopropanol in air has a value of 23.00 units and the

Physics

2 answers:

Y_Kistochka [10]2 years ago

7 0

Answer:

It's A & C

Explanation:

hichkok12 [17]2 years ago

4 0

Answer:

A and C

Explanation:

A.P.E.X

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Answer:

The car's displacement during this time is 25.65 meters.

Explanation:

Given that,

Final velocity of the car, v = 4.5 m/s

Deceleration of the car, $a=-2.7\ m/s^2$

Let u is the initial speed of the car. It is given by :

$v=u+at$

$u=v-at$

$u=4.5-(-2.7)\times 3$

u = 12.6 m/s

Let d is the car's displacement during this time. It can be calculated using second equation of motion as :

$d=ut+\dfrac{1}{2}at^2$

$d=12.6\times 3+\dfrac{1}{2}\times (-2.7)\times 3^2$

d = 25.65 meters

So, the car's displacement during this time is 25.65 meters. Hence, this is the required solution.

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3 years ago

A spaceship travels at approximately 0. 25c with respect to earth. this means 24 hours at the spaceship will be x hours to us on

Blababa [14]

The time passed on earth is mathematically given as

t' = 24.79 hrs

<h3>What is the time passed on earth?</h3>

Generally, the equation for is time mathematically given as

$t' = \gamma t$

Where

$\gamma = Lorentz\ factor \\\\\gamma = 1/ \sqrt {(1 - v^2/c^2)}$

$t' = t/ \sqrt {(1 - v^2/c^2)}$

Therefore

$t' = 24/ \sqrt {(1 - (0.25c/c)^2) }$

$t'= 24/ \sqrt {(1 - 0.25^2)$

t' = 24.79 hrs

In conclusion, the time passed on earth

t' = 24.79 hrs

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1 year ago

What is your theory on frame of reference?

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What is your theory on frame of reference?

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It is the idea of seeing something from a different perspective

Explanation:

Hope this helps!

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Which statement is correct? Theories are accepted as true when a single experiment yields similar results to another one. When a

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The third statement is correct.

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The relationship between distance from the sun and orbital period is that as the distance from the sun increases, the orbital pe

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Second law is it:))))))))

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2 years ago