A clock radio is rated as 30 w of power output. if the radio also draws 30 w at 120 v, which will the current draw be?

Comparing objects in a related group can reveal patterns among them. These patterns in turn can help us learn more about those o

rosijanka [135]

Answer:

C. All planets orbit the Sun in the same direction.

E. The orbits of the planets are evenly distributed in distance from the Sun.

F. All planets orbit the Sun in a roughly flat plane.

Explanation:

As we can see that due to big bang theory of planet formation we can say all planets revolve around the sun in circular orbit with almost in same plane

Size of the planets are unevenly distributed and they all revolve around the sun in same directions

so here correct options are

C. All planets orbit the Sun in the same direction.

E. The orbits of the planets are evenly distributed in distance from the Sun.

F. All planets orbit the Sun in a roughly flat plane.

5 0

3 years ago

There is a dropping of a coconut of 2kg mass. the speed of the coconut at the moment before it hits the ground is 40m s-1.

igor_vitrenko [27]

Mass=2kg
Velocity=40m/s

We know

$\boxed{\sf K.E=\dfrac{1}{2}mv^2}$

m denotes to mass
v denotes to velocity

$\\ \sf\longmapsto K.E=\dfrac{1}{2}\times 2\times 40^2$

$\\ \sf\longmapsto K.E=40^2$

$\\ \sf\longmapsto K.E=1600J$

6 0

3 years ago

Which of the following should you always use to protect yourself from hazardous moving parts of power tools and equipment

Andrew [12]

What are the following answers?

7 0

3 years ago

A jogger jogs around a circular track with a diameter of 275 m in 14.0 minutes. what was the jogger's average speed in m/s?

Pie

The jogger's average speed 1.03 m/s

<h3>The Speed and the Velocity of a Particle in a Circle</h3>

The speed of a particle is a circle will always be constant while the velocity will not. That is, velocity varies.

Given that a jogger jogs around a circular track with a diameter of 275 m in 14.0 minutes. First convert the minutes to seconds

Given parameters are;

Diameter = 275 m

Radius r = D/2 = 137.5 m

Time t = 14 minutes = 14 x 60s = 840 s

Speed V = 2πr ÷ t

V = ( 2 × π × 137.5 ) ÷ 840

V = 863.9 / 840

V = 1.028 m/s

Therefore, the jogger's average speed 1.03 m/s approximately

Learn more about Circular Motion here: brainly.com/question/20905151

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5 0

2 years ago

Suppose the ski patrol lowers a rescue sled carrying an injured skier, with a combined mass of 97.5 kg, down a 60.0-degree slope

Kitty [74]

a. 1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b.21,835 J work, in joules, is done by the rope on the sled this distance.

c. 23,170 J the work, in joules done by the gravitational force on the sled d. The net work done on the sled, in joules is 43,670 J.

<h3>What is friction work?</h3>

The work done by friction is the force of friction times the distance traveled times the cosine of the angle between the friction force and displacement

a. How much work is done by friction as the sled moves 28m along the hill?

ans. We use the formula:

friction work = -µ.mg.dcosθ

= -0.100 * 97.5 kg * 9.8 m/s² * 28 m * cos 60

= -1337.3 J

-1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b. How much work is done by the rope on the sled in this distance?

We use the formula:

Rope work = -m.g.d(sinθ - µcosθ)

rope work = - 97.5 kg * 9.8 m/s² * 28 m (sin 60 – 0.100 * cos 60)

= 26,754 (0.816)

= 21,835 J

21,835 J work, in joules, is done by the rope on the sled this distance.

c. What is the work done by the gravitational force on the sled?

By using the formula:

Gravity work = mgdsinθ

= 97.5 kg * 9.8 m/s² * 28 m * sin 60

= 23,170 J

23,170 J the work, in joules done by the gravitational force on the sled .

D. What is the total work done?

By adding all the values

work done = -1337.3 + 21,835 + 23,170

= 43,670 J

The net work done on the sled, in joules is 43,670 J.

Learn more about friction work here:

brainly.com/question/14619763

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4 0

2 years ago