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Pani-rosa [81]
3 years ago
14

A school's service club is sponsoring a dance in the

Mathematics
1 answer:
HACTEHA [7]3 years ago
8 0

Answer:

Yes, they only need 400 tickets to meet their goal, any more will exceed their goal.

Step-by-step explanation:

You might be interested in
The total amount paid on a 35 year loan was $98,000. If the interest rate was 4.1% and compounded monthly, what was the principa
Levart [38]

Answer:

The principal amount was $23,393.45

Step-by-step explanation:

The total amount paid on a 35 year loan was $98,000 at the rate of interest 4.1%

We will calculate Principal amount by this formula

A=P(1+\frac{r}{n})^{nt}

Where A = amount (98,000)

           P = Principal amount (P)

           r = rate of interest 4.1% (0.041)

           n = number of compounding interest monthly (12)

           t = time (35 years)

98,000=P(1+\frac{0.041}{12})^{(12)(35)}

98,000=P(1+0.003416)^{(420)}

98,000=P(1.003416)^{(420)}

98,000 = P(4.189386)

= 4.189386P = 98,000

P = \frac{98000}{4.189386}

P = 23,392.4494 ≈ $23,392.45

The principal amount was $23,393.45

5 0
4 years ago
Read 2 more answers
HELP! IS THIS PROPORTIONAL
MAXImum [283]

Answer:

Yes

Step-by-step explanation:

3 0
3 years ago
A=160, b=110, C=54. What is the distance between AB?
Schach [20]

Answer:

50

Step-by-step explanation:

answer is 50

3 0
3 years ago
Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov
mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

2t=(m+\frac{1}{2} ).\frac{\lambda}{n}

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm

Hence the thickness difference should be

t_1-t_2=131.58-75.19=56.39 \ nm

7 0
3 years ago
The points in the table lie on a line. Find the slope of the line.
Rina8888 [55]
5/2 or 2.5
Hope this helps!
6 0
3 years ago
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