All categories

3 years ago

Which of the following is an example of commensalism?

Chemistry

1 answer:

Contact [7]3 years ago

7 0

Answer: A tick on a deer

Explanation:

because commensalism is a type of symbiotic relationship in which one species benefits, while the other species is neither harmed nor helped

please put brainlest for me if you found this helpful

You might be interested in

Calculate the mass of butane needed to produce 72.9 grams of carbon dioxide

morpeh [17]

I got you
The molecular formula for the combustion of butane in oxygen is:
2 C4H10 + 13 O2 ---> 8 CO2 + 10 H20

You take the mass of carbon dioxide, 56.8g, divide by its molar mass, 44.01g/mol, to produce the moles of carbon dioxide. This is multiplied by the molar ratio of butane/CO2, (2/8) = 1/4, which gives the moles of butane required to produce the carbon dioxide. Multiply the number of moles of butane by its molar mass, 58.12g/mol, to produce the mass of butane. Mass of butane = 18.8g

8 0

3 years ago

Read 2 more answers

0.0000250 m in scientific notation

malfutka [58]

2.50 × 10 ^-5. Move your decimal until you get a whole number. Then count how many times you moved it and that is your exponent. So your exponent is -5 because you're going to the left, if you're going to the right it would be a positive number.

3 0

3 years ago

Zinc reacts with hydrochloric acid according to the reaction equation Zn ( s ) + 2 HCl ( aq ) ⟶ ZnCl 2 ( aq ) + H 2 ( g ) How ma

Katen [24]

Answer: 12.0 milliliters of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn.

Explanation:

moles = $\frac{\text {given mass}}{\text {Molar mass}}$

moles of zinc = $\frac{2.55g}{65.38g/mol}=0.0390moles$

The balanced chemical equation is :

$Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)$

According to stoichiometry:

1 mole of zinc reacts with = 2 moles of HCl

Thus 0.0390 moles of zinc reacts with = $\frac{2}{1}\times 0.0390=0.0780$ moles of HCl

To calculate the volume for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}$ .....(1)

Molarity of $HCl$ solution = 6.50 M

Volume of solution = ?

Putting values in equation 1, we get:

$6.50M=\frac{0.0780\times 1000}{\text{Volume of solution in ml}}$

${\text{Volume of solution in ml}}=12.0ml$

Thus 12.0 ml of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn

3 0

3 years ago

Using the bond energy data from your text (or the internet), determine (show calculations for) the approximate enthalpy change ,

aleksley [76]

Answer:

∆H= 438 KJ/mol

Explanation:

First, we have to find the energy bond values for each compound:

-) Cl-Cl = 243 KJ/mol

-) F-F = 159 KJ/mol

-) F-Cl = 193 KJ/mol

If we check the reaction we can calculate the number of bonds:

$Cl_2_(_g_)~+~3F_2_(_g_)~->~2ClF_3_(_g_)$

In total we will have:

-) Cl-Cl = 1

-) F-F = 3

-) F-Cl = 6

With this in mind. we can calculate the total energy for each bond:

-) Cl-Cl = (1*243 KJ/mol) = 243 KJ/mol

-) F-F = (3*159 KJ/mol) = 477 KJ/mol

-) F-Cl = (6*193 KJ/mol) = 1158 KJ/mol

Now, we can calculate the total energy of the products and the reagents:

Reagents = 243 KJ/mol + 477 KJ/mol = 720 KJ/mol

Products = 1158 KJ/mol

Finally, to calculate the total enthalpy change we have to do a subtraction between products and reagents:

∆H= 1158 KJ/mol-720 KJ/mol = 438 KJ/mol

I hope it helps!

7 0

3 years ago

Why did mendeleev switch iodine and tellurium?

Travka [436]

An example would be iodine has a lower relative atomic mass than tellurium, so it should come before tellurium in Mendeleev's table. In order to get iodine in the same group as the other elements with similar properties such as fluorine, chlorine, and bromine, he had to put it after tellurium, which broke his own rules.

6 0

3 years ago