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Ad libitum [116K]
3 years ago
5

What is the difference between sucrose? Table sugar? And Artificial Sweeteners?

Chemistry
1 answer:
liraira [26]3 years ago
3 0

<em>SUCROSE</em><em> </em><em>IS</em><em> </em><em>A</em><em> </em><em>NATURALLY</em><em> </em><em>OCCURRING</em><em> </em><em>SUGAR</em><em>, </em><em>COMMONLY</em><em> </em><em>KNOWN</em><em> </em><em>AS</em><em> </em><em>TABLE</em><em> </em><em>SUGAR</em><em>.</em><em> </em><em> </em><em>SUCRALOSE</em><em>, </em><em>ON</em><em> </em><em>THE</em><em> </em><em>OTHER</em><em> </em><em>HAND</em><em>, </em><em>IS</em><em> </em><em>AN</em><em> </em><em>ARTIFICIAL</em><em> </em><em>SWEETENER</em><em>, </em><em>PRODUCED</em><em> </em><em>IN</em><em> </em><em>A</em><em> </em><em>LAB</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELP</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>☺</em><em>☺</em><em>☺</em>

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A buffer contains 0.18 mol of propionic acid (C2H5COOH) and 0.26 mol of sodium propionate (C2H5COONa) in 1.20 L. What is the pH
Yuki888 [10]

Answer:

1) pH = 5.05

2) pH = 5.13

3) pH = 4.97

Explanation:

Step 1: Data given

Number of moles of propionic acid = 0.18 moles

Number of moles sodium propionate = 0.26 moles

Volume = 1.20 L

Ka = 1.3 * 10^-5    → pKa = 4.989

Step 2: Calculate concentrations

Concentration = moles / volume

[acid]= 0.18/ 1.2 =0.150 M

[salt]= 0.26/ 1.3 = 0.217 M

pH = 4.89 + log(0.217/0.150)=<u>5.05</u>

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What is the pH of the buffer after the addition of 0.02 mol of NaOH?

moles acid = 0.18 - 0.02 = 0.16

[acid]= 0.16/ 1.2=0.133 M

moles salt = 0.26 + 0.02 = 0.28

[salt]= 0.28/ 12=0.233

pH = 4.89 + log 0.233/ 0.133 = 5.13

What is the pH of the buffer after the addition of 0.02 mol of HI?

moles acid = 0.18+ 0.02 = 0.20 moles

[acid]= 0.20/ 1.2 = 0.167 M

[salt]= 0.26 - 0.02= 0.24 moles

[salt]= 0.24/ 1.2 = 0.20 M

pH = 4.89 + log 0.20/ 0.167= 4.97

8 0
3 years ago
True or False. Weather describes the atmospheric events that occur each day &amp; climate is the average weather pattern in an a
Ilia_Sergeevich [38]

Answer:

true

Explanation:

7 0
3 years ago
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NaOH is an Arrhenius base because it increases the concentration of hydroxide ions when dissolved in solution.
Licemer1 [7]

The answer is true, NaOH is and Arrhenius base.

7 0
3 years ago
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Calcium hydride (cah2) reacts with water to form hydrogen gas: cah2(s) + 2h2o(l) → ca(oh)2(aq) + 2h2(g) how many grams of cah2 a
andreev551 [17]
Using the ideal gas law equation, we can find the number of H₂ moles produced.
PV = nRT
Where P - pressure - 0.811 atm x 101 325 Pa/atm = 82 175 Pa
V - volume - 58.0 x 10⁻³ m³
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 32 °C + 273 = 305 K
substituting these values in the equation,
82 175 Pa x 58.0 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 305 K
n = 1.88 mol 

The balanced equation for the reaction is as follows;
CaH₂(s) + 2H₂O(l) --> Ca(OH)₂(aq) + 2H₂(g)
stoichiometry of CaH₂ to H₂ is 1:2
When 1.88 mol of H₂ is formed , number of CaH₂ moles reacted = 1.88/2 mol
therefore number of CaH₂ moles reacted = 0.94 mol
Mass of CaH₂ reacted - 0.94 mol x 42 g/mol  = 39.48 g of CaH₂ are needed
3 0
3 years ago
In ironmaking, iron metal can be separated from iron ore (Fe2O3) by heating the ore in a blast furnace in the presence of coke,
mel-nik [20]

The limiting reactant is iron ore, the theoretical yield of iron metal is 701.344 kg, and the theoretical yield of carbon dioxide is 413.292 kg.

<h3>Stoichiometric problem</h3>

From the equation of the reaction:

2 Fe_2O_3(s) + 3 C(s) --- > 4 Fe(s) + 3 CO_2(g)

The mole ratio of iron ore to carbon is 2:3.

Mole of 1000 kg of iron ore = 1000000/159.69

                                          = 6,262 moles

Mole of 120 kg carbon = 120000/12

                                 = 10,000 moles

Thus, it appears that the carbon is in excess while the iron ore is limited in availability.

The mole ratio of the iron ore and the iron produced is 1:2. Thus, the equivalent number of moles of iron produced will be:

              6,262 x 2 = 12,524 moles

Mass of 12,524 moles of iron = 12,524 x 56

                                                = 701,344 g or 701.344 kg

Thus, the theoretical yield of iron is 701.344 kg.

The mole ratio of the iron ore and the carbon dioxide produced is 2:3. The equivalent mole of carbon dioxide produced will be:

         6,262 x 3/2 = 9,393 moles

Mass of 9,393 moles carbon dioxide = 9,393 x 44

                                                         = 413,292 or 413.292 kg

The theoretical yield of carbon dioxide is, therefore, 413.292 kg.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

       

3 0
2 years ago
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