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Kryger [21]
3 years ago
7

A culture started with 3000 bacteria. After 4 hours, it grew to 3,600 bacteria. Predict how many bacteria will be present after

10 hours. Round your answer to the nearest whole number. Use exponential growth formula
Mathematics
1 answer:
Vlad [161]3 years ago
4 0
Hello Shannonrodrigue. You can solve this by setting up an exponential growth equation.

A = A_ob^t
3600 = 3000b^4

Now we solve for b
3600 = 3000b^4
\frac{3600}{3000} = \frac{3000b^{4}}{3000}
\frac{6}{5} = b^4
\sqrt[4]{\frac{6}{5}} = \sqrt[4]{b^4}
\sqrt[4]{\frac{6}{5}} = b

Now that we have found b, we can use the equation A = 3000b^t to predict how many bacteria will be present after 10 hours.
b = \sqrt[4]{\frac{6}{5}}
t = 10
A = 3000b^t
A = 3000\sqrt[4]{\frac{6}{5}}^{10} = 4732.3228 = 4732

Answer = 4732



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What is the greatest common factor of 42, 30, and 45​
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Answer:

GCF = 3

Step-by-step explanation:

Express the numbers as a product of their primes.

42 = 2 × 3 + 7

30 = 2 × 3 × 5

45 = 3 × 3 × 5

Identify the prime factors common to all 3 numbers.

common prime factor = 3 , thus

GCF = 3

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2 years ago
2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA
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Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

A=45e^{-0.0045(t)}

a) To find the initial amount of this substance

At t=0, we get

A=45e^{-0.0045(0)}A=45e^0

We know that e^0=1 ( anything to the power zero is 1)

we get,

A=45

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

\frac{45}{2}=45e^{-0.0045(t)}

\frac{1}{2}=e^{-0.0045(t)}

Taking natural logarithm on both sides we get,

\ln (\frac{1}{2})=-0.0045(t)^{}(-1)\ln (\frac{1}{2})=0.0045(t)\ln (\frac{1}{2})^{-1}=0.0045(t)\ln (2)=0.0045(t)0.6931=0.0045(t)t=\frac{0.6931}{0.0045}t=154.02

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

A=45e^{-0.0045(2500)}A=45e^{-11.25}A=45\times0.000013=0.000585A=0.000585

The amount of substance will be present around in 2500 years is 0.000585 grams

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8 months ago
BRAINLIEST +10 POINTS
Oksanka [162]
The forth one I can’t type that tho
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3 years ago
I need help proving this ASAP
Ket [755]

Answer:

See explanation

Step-by-step explanation:

We want to show that:

\tan(x +  \frac{3\pi}{2} )  =  -   \cot \: x

One way is to use the basic double angle formula:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ \sin(x)  \cos( \frac{3\pi}{2} )  +   \cos(x)  \sin( \frac{3\pi}{2}) }{\cos(x)  \cos( \frac{3\pi}{2} )   -    \sin(x)  \sin( \frac{3\pi}{2}) }

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ \sin(x) ( 0)  +   \cos(x) (  - 1) }{\cos(x) (0)   -    \sin(x) (  - 1) }

We simplify further to get:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ 0  -   \cos(x) }{0 +    \sin(x) }

We simplify again to get;

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{- \cos(x) }{ \sin(x) }

This finally gives:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  -  \cot(x)

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If 4 + 6 = 10, does (4 + 6) X 3= 10 X 3? Why or why not?​
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