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enyata [817]
3 years ago
6

Write an equation for two angles A and B that are supplementary.

Mathematics
1 answer:
Alinara [238K]3 years ago
3 0

Answer:

A. a + b = 180 is the correct option.

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Compare -15/4 and -3 3/8
muminat

Answer:

-15/4 > -3 3/8

Step-by-step explanation:

I converted -15/4 into a mixed number with a denominator of 8. First, I made it a mixed number (-3 1/4) and then I converted it to eighths (-3 2/8). Compared to -3 3/8, -15/4 is larger.

4 0
3 years ago
The population of a town is 32600 about 27% are over 60 years old about 19% are 16 or under how many are between 16 and 60
r-ruslan [8.4K]
Answer: 17604

Explanation: In order to find a percentage, mulptiply the population by the percentage with a decimal in front. Like this:

32600 • .46

I got 46 because 27 + 19 = 46

Once you get that answer, subtract it from the original total

32600 - 14996 = 17604

You're done! Hope this helps



3 0
3 years ago
Helpphelpphelpphelpphelpp<br> helpphelpphelpphelpphelpphelpphelpphelpphelpphelpphelpphelpphelpp
umka2103 [35]

Answer:

wait what?

Step-by-step explanation:

7 0
3 years ago
Please Help I DOn't Understand This Lesson
elena55 [62]

<u>Set up the composite function and simplify. </u>

f = 2x + 3,

g = -x^2 + 5,

f(x) o g(x):

D. 134

4 0
3 years ago
Which statements are true about the linear inequality y &gt; 3/4x – 2? Check all that apply. The slope of the line is –2. The gr
pishuonlain [190]
You can draw the area bounded by the unequality y\ \textgreater \  \frac{3}{4} x-2 in following way:

1. Draw a dashed line y=\frac{3}{4} x-2 with a slope \frac{3}{4} (a dashed, because all points from this line, for example when x=0, y=-2 do not belong to the area);

2. Define which part (under the line or over the line) is suitable by substituting values. For example, when x=0 and y=0 you obtain that 0\ \textgreater \  \frac{3}{4} \cdot 0-2 is a right unequality, that means that the point (0,0) is a solution and belongs to the area;

3. Shade that part of the plane to which point (0,0) belongs, you receive the area over the line (see image).

From the done steps you can see that only fourth statement is true.



4 0
3 years ago
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