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3 years ago

A minibus drives 101 km in 1 hour. What is its average speed in kilometers per hour?

Mathematics

1 answer:

tekilochka [14]3 years ago

4 0

Answer:

Step-by-step explanation:

Average speed is distance divided by time.

s=(101km)/(1hr)

s=101 km/hr

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melomori [17]

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2.26666666667 is the answer

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2 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

LiRa [457]

Answer:

x = 7, -7

Step-by-step explanation:

(2x-1)(3x+2)+x+292

3x - 2x +x = 2 - 1 + 292

(6)x - 294 = 6(x - 49)

Use communicative property of multiplication

Example: (A+B)(A-B)

$Ax^{2} -AB+BA-Bx^{2} =Ax^{2} -AB+AB-Bx^{2} =\\Ax^{2} -Bx^{2}$

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2 years ago

Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

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b.a = 20-14

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||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

<em>Hence the projection of b unto a is expressed as </em> $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$ <em></em>

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3 years ago

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VMariaS [17]

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Step-by-step explanation:

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gladu [14]

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Step-by-step explanation:

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