In redox reaction electrons are transferred
Redox reaction involve both reducing of b agent and oxidizing agent. reducing agent acts as electrons donor while oxidizing agent acts as electron acceptor
for example formation of Hydrogen fluoride (HF)
that is H2 + F2 = HF
by breaking the equation
H2 = 2 H^+ 2e-
F2 + 2e= 2f-
hydrogen move from oxidation from zero( 0 )to positive one ( +1 )therefore hydrogen is oxidized. Fluorine move from oxidation state of zero(0) to oxidation state of negative one(-1) therefore fluorine is reduced.
Answer:
H₂SO₄ (aq) + H₂O (l) → HSO₄⁻ (aq) + H₃O⁺ (aq)
HSO₄⁻ (aq) + H₂O (l) ⇄ SO₄⁻²(aq) + H₃O⁺ (aq) Ka
Explanation:
The sulfuric acid is a dyprotic acid.
It is a considered a strong acid but only the first deprotonation is strong.
Second deprotonation is totally weak
That's why we have equilibrium when it release the second proton.
Since a deprotonation is treated for a weak acid, the acid is considered not to completely dissociate, that's why the equilibrium
Answer:
C.Hydrogen
Explanation:
The hydrogen atom contains 1 proton and 1 electron, but no neutrons.
Those Hydrogen atoms which are present at alpha position to carbonyl group are mildly acidic in nature. When such acidic proton containing carbonyl compounds are treated with strong base, they yield enolates. The negative charge created on alpha carbon resonates and shifts to carbonyl oxygen resulting in formation of carbon double bond carbon.
In <span>tert−butyl methyl ketone there are two carbons at each alpha position. Among these two carbons only methyl carbon contains hydrogen atoms while the second one is bonded to further three carbons making it Quaternary carbon. The base abstracts proton from methyl group and enolate is formed.
</span>tert−butyl methyl ketone in this case acts as acid, Hydroxyl ion acts as base, while the enolate generated is the conjugate base of <span>tert−butyl methyl ketone and Water produced is the conjugate acid of hydroxide ion.</span>
Answer:
110.984 ?
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Explanation: