Draw structures corresponding to the following IUPAC names:(a) (Z)-2-Ethyl-2-buten-1-ol (b) 3-Cyclohexen-1-ol(c) trans-3-Chloroc
1 answer:
Answer:
Draw structures corresponding to the following IUPAC names:(a) (Z)-2-Ethyl-2-buten-1-ol (b) 3-Cyclohexen-1-ol(c) trans-3-Chlorocycloheptanol (d) 1,4-Pentanediol(e) 2,6-Dimethylphenol (f ) o-(2-Hydroxyethyl)phenol
Explanation:
According to IUPAC rules, the name of a compound is:
Prefix+root word+suffix
1) Select the longest carbon chain and it gives the root word.
2) The substituents give the prefix.
3) The functional group gives the secondary suffix and the type of carbon chain gives the primary suffix.
The structure of the given compounds are shown below:
You might be interested in
Answer:
Mass of rock = 4533.4 kg
Explanation:
Percent composition is percentage by the mass of element present in the compound.
Given that the is 82 % by mass.
It means that 82 kg of is present in 100 kg of rock
To find the mass of rock which contains 2600 kg of iron
2600 kg = 2600*1000 g
2 moles of iron are present in 1 mole of
Molar mass of iron = 55.845 g/mol
Mass of 2 moles = 55.845 * 2 = 111.69 g/mol
Molar mass of = 159.69 g/mol
It means,
111.69 g of iron are present in 159.69 g of
1 g of iron is present in 159.69/111.69 g of
2600*1000 g is present in (159.69/111.69)*2600*1000 g of
Mass of = 3717378.47 g =3717.38 kg
Thus,
82 kg of is present in 100 kg of rock
1 kg of is present in 100/82 kg of rock
3717.38 kg of is present in (100/82)*3717.38 kg of rock
Mass of rock = 4533.4 kg