Answer:
0.32M
Explanation:
Given parameters:
Number of moles of NaCl = 1.29moles
Volume of solution = 4liters = 4dm³
Unknown:
Molarity of solution = ?
Solution:
Molarity is one the ways of expressing the concentration of a solute in a solution. It is given as;
Molarity = 
The unit is given as M which is mol/dm³
Input the parameters and solve;
Molarity = 
= 0.32mol/dm³ or 0.32M
The overall fusion reaction is the conversion of Hydrogen to Helium
Answer:
A
Explanation:
B describes a strong base, C just isn't true there are only 7 strong acids, D describes a weak acid
The correct answer is: [C]:
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"<span>pressure and the number of gas molecules are directly related."
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<u>Note</u>: The conclusion was: "</span> as the pressure in a system increases, the number of gas molecules increases" — over the course of many trials.
This means that the "pressure" and the "number of gas molecules" are directly related.
Furthermore, this conclusion is consistent with the "ideal gas law" equation:
" PV = nRT " ;
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in which:
"P = Pressure" ;
"n = number of gas molecules" ;
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All other factors held equal, when "n" (the "number of gas molecules")
increases in value (on the "right-hand side" of the equation), the value for "P" (the "pressure" — on the "left-hand side" of the equation), increases.
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Answer:
6.4 × 10^-10 M
Explanation:
The molar solubility of the ions in a compound can be calculated from the Ksp (solubility constant).
CaF2 will dissociate as follows:
CaF2 ⇌Ca2+ + 2F-
1 mole of Calcium ion (x)
2 moles of fluorine ion (2x)
NaF will also dissociate as follows:
NaF ⇌ Na+ + F-
Where Na+ = 0.25M
F- = 0.25M
The total concentration of fluoride ion in the solution is (2x + 0.25M), however, due to common ion effect i.e. 2x<0.25, 2x can be neglected. This means that concentration of fluoride ion will be 0.25M
Ksp = {Ca2+}{F-}^2
Ksp = {x}{0.25}^2
4.0 × 10^-11 = 0.25^2 × x
4.0 × 10^-11 = 0.0625x
x = 4.0 × 10^-11 ÷ 6.25 × 10^-2
x = 4/6.25 × 10^ (-11+2)
x = 0.64 × 10^-9
x = 6.4 × 10^-10
Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M
