What is the empirical formula of a compound that is 24.42 % calcium, 17.07 % nitrogen, and 58.5% oxygen?
1 answer:
Answer:
Explanation:
When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.
So:
24.42 % = 24.42 g Ca, 17.07% = 17.07g N, 58.5% = 58.5g O
The next step is to divide each mass by their molar mass to convert your grams to moles.
24.42/40.08 = 0.6092 mol
17.07/14.01 = 1.218 mol
58.85/15.99 = 3.680 mol
Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subcripts) of the empircal formula.
0.6092 mol/0.6092 mol = 1
1.218 mol/0.6092 mol = 2
3.680 mol/0.6092 mol = 6
So the empirical formula is
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Taking into account about the ideal gas law, the mass of fluorine gas is 63.2244 grams.
<h3>What is ideal gas law</h3>An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
- P is the gas pressure.
- V is the volume that occupies.
- T is its temperature. The universal constant of ideal gases R has the same value for all gaseous substances.
- R is the ideal gas constant.
- n is the number of moles of the gas.
The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
<h3>Mass of fluorine gas</h3>In this case, you know:
- P= 850 mmHg= 1.11842 atm (being 1 mmHg= 0.00131579 atm)
- V= 45.5 L
- T =100 °C= 373 K (being 0°C= 273 K)
- R= 0.082
- n= ?
Replacing in the ideal gas law:
1.11842 atm ×45.5 L = n×0.082 × 373 K
Solving:
n= (1.11842 atm ×45.5 L)÷ (0.082 × 373 K)
<u><em>n= 1.6638 moles</em></u>
The molar mass of F₂ is 38 g/mole. Then you can apply the folowing rule of three: If by definition of molar mass 1 mole of the compound contains 38 grams, 1.6638 moles of the compound contains how much mass?
<u><em>mass= 63.2244 grams</em></u>
Finally, the mass of fluorine gas is 63.2244 grams.
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the ideal gas law:
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Answer:
the value of molar absorptivity is 229000
Explanation:
given data
phenol phthalein solution = 0.050 g
total volume = 100.0 ml
dilute = 100.0 ml
diluted sample = 0.18
solution
we get here concentration that is express as
concentration = ( mass of solute × 1000 ) ÷ ( molar mass of solute × volume of solution ) .............1
put here value
concentration =
concentration = 0.00157 M
and here dillution equation is express as
c1 × v1 = c2 × v2 .................2
here c1 and c2 is initial and final concentration
and v1 and v2 is initial and final volume
put here value
0.001571 × 0.050 = c2 × 100
c2 = 7.855 × M
and
now we get molar by absorbance equation that is
A = E × C × l ................3
here A is absorbance and E is molar and c is absorptivity and l is path length
put here value
0.18 = E × 7.855 × × 1
E = 229000