Hello!
<span>We have the following statement data:
</span>
Data:




<span>As the percentage is the mole fraction multiplied by 100:
</span>

<span>The mole fraction will be the percentage divided by 100, thus:
</span><span>What is the partial pressure of oxygen in this mixture?
</span>



<span>To calculate the partial pressure of the oxygen gas, it is enough to use the formula that involves the pressures (total and partial) and the fraction in quantity of matter:
</span>
In relation to

:




<span>
Answer:
</span><span>
b. 320.0 mm hg </span>
For both of them, used the balanced equation and it’s mole ratio to convert whatever you need to into moles. See the attacked work.
1) D 5 mols
2) A 0.55 mols
The answeris c, chemicalchange because the atoms in woodand oxygen are rearranged.
Answer:

Explanation:
We can use the Ideal Gas Law and solve for T.
pV = nRT
Data
p = 1.25 atm
V = 25.0 L
n = 2.10 mol
R = 0.082 06 L·atm·K⁻¹mol⁻¹
Calculations
1. Temperature in kelvins

2. Temperature in degrees Celsius
