All categories

3 years ago

Write the complementary DNA strand to A-C-C-G-T-T-A-C-G-C-A

Chemistry

2 answers:

barxatty [35]3 years ago

6 0

Answer:T-G-G-C-A-A-T-G-C-G-T

Explanation:adenine always pairs with thymine and thymine always pairs with adenine

Cytosine always pairs with guanine and guanine always pairs with cytosine

posledela3 years ago

3 0

Answer:

T-G-G-C-A-A-T-G-C-G-T

Explanation:

use AT GC

You might be interested in

The empirical formula for a compound is CH2. Its molar mass is 140.1 g/mol. What is its molecular formula?

ki77a [65]

The empirical formula CH₂ has a mass [(12 × 1) + (1 × 2)] = 14 g/mol

If the empirical formula is 14 g/mol,
and the molecular formula is ~140 g/mol

Then the multiple is = 140 g/mol ÷ 14 g/mol
= 10

Therefor the molecular formula is 10(CH₂) = C₁₀H₂₀

3 0

3 years ago

Read 2 more answers

A sample of hydrated tin (II) chloride (SnCl2) has a mass of 4.90 g. When it is dehydrated, it has a mass of 4.10 g. Which is th

Usimov [2.4K]

Answer:

SnCl₂·2 H₂O.

Explanation:

Relative atomic mass data from a modern periodic table:

Sn: 118.710;
Cl: 35.45;
H: 1.008;
O: 15.999.

How many moles of SnCl₂ formula units in this sample?

The first mass 4.90 grams contain both the SnCl₂ formula units and a number of water molecules. Luckily, the mass of the dehydrated salt 4.10 grams contains only SnCl₂.

Formula mass of tin (II) chloride SnCl₂:

$M(\rm SnCl_2) = 118.710 + 2\times 35.45 = 189.610\; g\cdot mol^{-1}$ .

Number of moles of tin (II) chloride SnCl₂ formula units in this sample:

$\displaystyle n(\mathrm{SnCl_2}) = \frac{m}{M} = \rm \frac{4.10\; g}{189.610\; g\cdot mol^{-1}} = 0.0216233\; mol$ .

How many moles of water molecules H₂O in this sample?

Water of crystallization exist as H₂O molecules in typical hydrated salts. The molar mass of these molecules will be:

$M(\rm H_2O) = 2\times 1.008 + 15.999 = 18.015\; g\cdot mol^{-1}$ .

The mass of water in the hydrated salt is the same as the mass that is lost when the water molecules are removed and the salt is dehydrated.

In other words,

$\begin{aligned}m(\text{Water of Hydration})&=m(\text{Hydrated Sample}) - m(\text{Anhydrous Sample}) \\ & = \rm 4.90\; g - 4.10\; g \\ &= \rm 0.80\; g\end{aligned}$ .

$\displaystyle n(\mathrm{H_2O}) = \frac{m}{M} = \rm \frac{0.80\; g}{18.015\; g\cdot mol^{-1}} = 0.0444074\; mol$ .

What's the coefficient in front of water in the formula of this hydrated salt? In other words, how many water molecules are there in the compound for each SnCl₂ formula unit?

$\displaystyle \frac{n(\mathrm{H_2O})}{n(\mathrm{SnCl_2})} = 2.05 \approx 2$ .

There are approximately two water molecules for each SnCl₂ formula unit. The formula of this compound shall thus be $\rm SnCl_2 \cdot 2H_2 O$ .

6 0

3 years ago

To make the future development more eco-friendly and decrease water pollution from run-off, choose one of the following recommen

ELEN [110]

Answer:

construct using only recycled materials ^^

Explanation:

5 0

3 years ago

What processes turn sediment into sedimentary rock?

antiseptic1488 [7]

A clastic sedimentary rock is composed of silicate minerals and rock fragments. They are transported by moving fluids such as sedimentation due to gravity and are deposited in the area where it stays. They are composed mostly of feldspar, quartz, rock (lithic) fragments, clay minerals and mica.

7 0

3 years ago

Read 2 more answers

F 2.50 × 10−2 g of solid Fe(NO3)3 is added to 100. ML of a 1.0 × 10−4 M NaOH solution, will a precipitate form? (ksp=4 × 10−38 f

vladimir1956 [14]

Answer:

A precipitate will be formed

Explanation:

The Ksp equilibrium of Fe(OH)₃ is:

Fe(OH)₃ (s) ⇄ Fe³⁺(aq)+ 3OH⁻(aq)

And its expression is:

Ksp = 4x10⁻³⁸ = [Fe³⁺] [OH⁻]³

Where the concentrations are concentrations in molarity in equilibrium,

We can write Q as:

Q = [Fe³⁺] [OH⁻]³

Where [] are actual concentrations in molarity of each specie.

When Q>= Ksp; a precipitate is formed,

When Q< Ksp no precipitate is produced:

[OH⁻] = [NaOH] = 1.0x10⁻⁴M

[Fe²⁺] = 2.50x10⁻²g * (1mol / 179.85g) / 0.100L = 1.39x10⁻³M

179.85g/mol is molar mass of Fe(NO₃)₂ and the volume of the solution is 0.100L = 100mL

Q = [Fe³⁺] [OH⁻]³

Q = [ 1.39x10⁻³] [ 1.0x10⁻⁴]³

Q = 3.8x10⁻¹⁵

As Q >> Ksp; A precipitate will be formed

7 0

3 years ago