No, the cone and the cylinder can't have congruent heights and bases.
<h3>
is it possible that the two cones have congruent bases and congruent heights?</h3>
The volume of a cylinder of radius R and height H is:
V = pi*R^2*H
And for a cone of radius R and height H is:
V = pi*R^2*H/3
So, for the same dimensions R and H, the cone has 1/3 of the volume of the cylinder.
Here, the cylinder has a volume of 120cm³ and the cone a volume of 360cm³, so the cone has 3 times the volume of the cylinder.
This means that the measures must be different, so the cone and the cylinder can't have congruent heights and bases.
If you want to learn more about volumes:
brainly.com/question/1972490
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Answer:
x = 15
Step-by-step explanation:
x + 7 = 22
Subtract 7 from each side
x+7-7 = 22-7
x=15
Answer: 50000
Step-by-step explanation:
Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.
Rules for significant figures:
Digits from 1 to 9 are always significant and have infinite number of significant figures.
All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.
All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.
All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.
All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.
Thus 52961 when rounded off to one significant figure will be 50000.
For x,
(32+x)/2=14
32+x=14*2
32+x=28
x=28-32
x=-4
For y,
(40+y)/2=26
40+y=26*2
40+y=52
y=52-40
y=12
Therefore coordinates of B(-4,12)
Hope this helps!
Answer:
"C" =14
Step-by-step explanation:
14+(-12)=-12+c
-12+c=14+(-12)
-12+c=14-12
-12+c+12=2+12
c=14
