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2 years ago

How would you pick the right kind of fluid to use in your hydraulic lift?

Chemistry

2 answers:

Semenov [28]2 years ago

5 0

R&o hydraulic fluid
aw32
and aw46
are some good oils

love history [14]2 years ago

3 0

Answer:you would pick the fluid by seeing what would work such as gas in a truck or car you need to know what would work best and the best power for the lift

Explanation:

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Why must all chemical equations be balanced?

Lera25 [3.4K]

If the equation is not balanced, you have extra of one substance. If you try to do an experiment, you could wind up with a totally different outcome. Its kind of like baking a cake. If the ingredients aren't the right amounts, you dont get an edible cake.

8 0

3 years ago

The small intestine shown below contains lymphatic vessels but no capillaries. Which nutrient will be absorbed by this small int

Bumek [7]

Answer:

fatty acids

Explanation:

8 0

2 years ago

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How many pennies are in $2,020.20?

Nata [24]

Answer:

202,020 pennies

Explanation:

The amount of pennies in 1 dollar is 100.

Basically, you just multiply the whole dollar amount (2020) by 100 and then add 20 to find the amount of pennies.

(2020)(100)+20= 202,000+20= 202,020 pennies.

5 0

2 years ago

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Suppose a group of volunteers is planning to build a park near a local lake. The lake is known to contain low levels of arsenic

Kisachek [45]

Answer:

A) 10.75 is the concentration of arsenic in the sample in parts per billion .

B) 7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

C) It will take 1.37 years to remove all of the arsenic from the lake.

Explanation:

A) Mass of arsenic in lake water sample = 164.5 ng

The ppb is the amount of solute (in micrograms) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

$\text{ppb}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^9$

Both the masses are in grams.

We are given:

Mass of arsenic = 164.5 ng = $164.5\times 10^{-9} g$

$1 ng=10^{-9} g$

Volume of the sample = V = $15.3 cm^3$

Density of the lake water sample ,d= $1.00 g/cm^3$

Mass of sample = M = $d\times V=1.0 g/cm^3\times 15.3 cm^3=15.3 g$

$ppb=\frac{164.5\times 10^{-9} g}{15.3 g}\times 10^9=10.75$

10.75 is the concentration of arsenic in the sample in parts per billion.

Mass of arsenic in $1 cm^3$ of lake water = $\frac{164.5\times 10^{-9} g}{15.3}=1.075\times 10^{-8} g$

Mass of arsenic in $0.710 km^3$ lake water be m.

$1 km^3=10^{15} cm^3$

Mass of arsenic in $0.710\times 10^{15} cm^3$ lake water :

$m=0.710\times 10^{15}\times 1.075\times 10^{-8} g=7,633,660.130 g$

1 g = 0.001 kg

7,633,660.130 g = 7,633,660.130 × 0.001 kg=7,633.660130 kg ≈ 7,633.66 kg

7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.

Days required to remove 1 kilogram of arsenic from the lake water :

$\frac{2.74}{41.90} days$

Then days required to remove 7,633.66 kg of arsenic from the lake water :

$=7,633.66\times \frac{2.74}{41.90} days=499.19 days$

1 year = 365 days

499.19 days = $\frac{499.19}{365} years = 1.367 years\approx 1.37 years$

It will take 1.37 years to remove all of the arsenic from the lake.

3 0

3 years ago

How can we regain the hardness of water by adding lime?

Maru [420]

Answer:

due to the bicarbonate of CaCO3

5 0

2 years ago

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