Answer:
Due to the presence of caustic soda in sodium hypo chlorite, the pH of the water is increased. When sodium hypo chlorite dissolves in water, two substances form, which play a role in for oxidation and disinfection. These are hypochlorous acid (HOCl) and the less active hypochlorite ion (OCl-).
Explanation:
When an organism is buried quickly there is less decay and better the chance for it to be persevere. The hard parts of the organism such as bones, shells, and teeth have a better chance of becoming fossils that softer parts of the organism. HARD BONES.
Density increases with the temperature, true.
Answer:
Los tripletes de nucleótidos de las moléculas de ADN y ARN que transportan información genética en las células vivas.
Explanation:
Answer:
(a) 3:2; (b) 2:1
Explanation:
The Law of Multiple Proportions states that when two elements A and B combine to form two or more compounds, the masses of B that combine with a given mass of A are in the ratios of small whole numbers.
That is, if one compound has a ratio r₁ and the other has a ratio r₂, the ratio of the ratios r is in small whole numbers.
(a) Ammonia and hydrazine.
In ammonia, the mass ratio of H:N is r₁ = 0.2158/1
In hydrazine, the mass ratio of H:N is r₂ = 0.1439/1
The ratio of the ratios is:
![r = \dfrac{r_{1}}{r_{2}} = \dfrac{ 0.2158}{0.1439} = \dfrac{1.500 }{1} = \dfrac{2.999}{2} \approx \mathbf{\dfrac{3}{2}}\\\\\text{The relative amounts of H in the two compounds are in the ratio }\boxed{\mathbf{\dfrac{3}{2}}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cdfrac%7Br_%7B1%7D%7D%7Br_%7B2%7D%7D%20%3D%20%5Cdfrac%7B%200.2158%7D%7B0.1439%7D%20%3D%20%5Cdfrac%7B1.500%20%7D%7B1%7D%20%3D%20%5Cdfrac%7B2.999%7D%7B2%7D%20%5Capprox%20%5Cmathbf%7B%5Cdfrac%7B3%7D%7B2%7D%7D%5C%5C%5C%5C%5Ctext%7BThe%20relative%20amounts%20of%20H%20in%20the%20two%20compounds%20are%20in%20the%20ratio%20%7D%5Cboxed%7B%5Cmathbf%7B%5Cdfrac%7B3%7D%7B2%7D%7D%7D)
(b) Nitrogen oxides
In nitrogen monoxide, the mass ratio of O:N is r₁ = 1.142/1
In dinitrogen monoxide, the mass ratio of O:N is r₂ = 0.571/1
The ratio of the ratios is:
![r = \dfrac{r_{1}}{r_{2}} = \dfrac{ 1.142}{0.571} = \dfrac{2.000 }{1} \approx \mathbf{\dfrac{2}{1}}\\\\\text{The relative amounts of O in the two compounds are in the ratio }\boxed{\mathbf{\dfrac{2}{1}}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cdfrac%7Br_%7B1%7D%7D%7Br_%7B2%7D%7D%20%3D%20%5Cdfrac%7B%201.142%7D%7B0.571%7D%20%3D%20%5Cdfrac%7B2.000%20%7D%7B1%7D%20%5Capprox%20%5Cmathbf%7B%5Cdfrac%7B2%7D%7B1%7D%7D%5C%5C%5C%5C%5Ctext%7BThe%20relative%20amounts%20of%20O%20in%20the%20two%20compounds%20are%20in%20the%20ratio%20%7D%5Cboxed%7B%5Cmathbf%7B%5Cdfrac%7B2%7D%7B1%7D%7D%7D)