Answer:
I don't exactly know how to answer this, maybe I need more information. But if not, then all he can do is add one gallon of yellow paint and one gallon of blue paint. If that's all the paint he has, that is all he can add. Is there a diagram that's supposed to go with this? If not, hope I answered your quesiton.
Answer:
Option 3
Step-by-step explanation:
![{2}^{ \frac{4}{3} } = \sqrt[3]{ {2}^{4} } = \sqrt[3]{16}](https://tex.z-dn.net/?f=%20%7B2%7D%5E%7B%20%5Cfrac%7B4%7D%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B%20%7B2%7D%5E%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B16%7D%20)
Answer:
(a) 0.007238 or 07238%
(b) 0.003468 or 0.3468%
Step-by-step explanation:
(a) Since all it takes is one defective rivet for a seam to be reworked. The probability of a defective rivet 'p' for 16% of seams needing reworking is:
![1-(1-p)^{24} = 0.16\\1-p = \sqrt[24]{0.84}\\p=0.007238](https://tex.z-dn.net/?f=1-%281-p%29%5E%7B24%7D%20%3D%200.16%5C%5C1-p%20%3D%20%5Csqrt%5B24%5D%7B0.84%7D%5C%5Cp%3D0.007238)
The probability that a rivet is defective 0.007238 or 0.7238%.
(b) To ensure that only 8% of seams need reworking, the probability 'p' must be:
![1-(1-p)^{24} = 0.08\\1-p = \sqrt[24]{0.92}\\p=0.003468](https://tex.z-dn.net/?f=1-%281-p%29%5E%7B24%7D%20%3D%200.08%5C%5C1-p%20%3D%20%5Csqrt%5B24%5D%7B0.92%7D%5C%5Cp%3D0.003468)
In order to ensure that only 8% of all seams need reworking, the probability of a defective rivet should be 0.003468 or 0.3468%.