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KonstantinChe [14]
3 years ago
6

2x^2-5x+1=0 solve using quadratic formula

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

x=(5±√17)/4, or x ≈  2.281 and 0.219

Step-by-step explanation:

2x^{2} -5x+1\\

plug into quadratic formula

5+- \sqrt{(-5)-4(2)(1)}/2(2)

simplify

5+-\sqrt{25-8} /4

\frac{5+-\sqrt{17} }{4}   ≈  2.281 and 0.219

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Liam is making barbecue ribs over a fire. The internal temperature of the ribs when he starts cooking is 40°F. During each hour
Soloha48 [4]

Answer: You need to wait at least 6.4 hours to eat the ribs.

t ≥ 6.4 hours.

Step-by-step explanation:

The initial temperature is 40°F, and it increases by 25% each hour.

This means that during hour 0 the temperature is 40° F

after the first hour, at h = 1h we have an increase of 25%, this means that the new temperature is:

T = 40° F + 0.25*40° F = 1.25*40° F

after another hour we have another increase of 25%, the temperature now is:

T = (1.25*40° F) + 0.25*(1.25*40° F) = (40° F)*(1.25)^2

Now, we can model the temperature at the hour h as:

T(h) = (40°f)*1.25^h

now we want to find the number of hours needed to get the temperature equal to 165°F. which is the minimum temperature that the ribs need to reach in order to be safe to eaten.

So we have:

(40°f)*1.25^h = 165° F

1.25^h = 165/40 = 4.125

h = ln(4.125)/ln(1.25)  = 6.4 hours.

then the inequality is:

t ≥ 6.4 hours.

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How do you solve this URGENT (50pts)
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y = mx + b  [where m is slope, b is y-intercept]

<u>Make y the subject</u>:

\sf \rightarrow  3y = 2 - x

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\sf \rightarrow y = -\dfrac{x}{3} + \dfrac{2}{3}

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Identify the GCF of 6x^2y^2 − 8xy^2 + 10xy
myrzilka [38]

Answer:

The GCF for the numerical part is 2

Step-by-step explanation:

6x^2y^2-8xy^2+10xy

It contains both numbers and variables, there are two steps to find the GCF(HCF).

1). Find the GCF for the numerical part 6, -8,10

2). Find the GCF for the variable part x^2,y^2,x^1,y^2,x^1,y^3

3).Multiply the values together.

Find the common factors for the numerical part:

6,-8,10

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Factors of -8

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Factors of 10

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Common factors of 6,-8, 10 are 1,2

The GCF Numerical=2

The GCF Variable= xy^2

Multiply the GCF of the numerical part 2 and the GCF of the variable part xy^2, and you'll get 2xy^2

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