Answer:
Step-by-step explanation:
The perimeter of a polygon is equal to the sum of all the sides of the polygon. Quadrilateral PTOS consists of sides TP, SP, TO, and SO.
Since TO and SO are both radii of the circle, they must be equal. Thus, since TO is given as 10 cm, SO will also be 10 cm.
To find TP and SP, we can use the Pythagorean Theorem. Since they are tangents, they intersect the circle at a 
, creating right triangles 
and 
.
The Pythagorean Theorem states that the following is true for any right triangle:
, where 
is the hypotenuse, or the longest side, of the triangle
Thus, we have:
Since both TP and SP are tangents of the circle and extend to the same point P, they will be equal.
What we know:
Thus, the perimeter of the quadrilateral PTOS is equal to 
It is 9:4.
Reason: divide both numbers by a common multiple, which is 7.
In light of the fact that point y is the point at which segment xz is divided, the value of the variable an is equal to 4.
<h3>How can I determine what the value of the variable an is?</h3>
Due to the fact that point y divides segment xz into two distinct halves, the following equation may be used to get segment xz's total length:
xz = xy + yz.
The following are the parameters for the test:
xy = 7a. yz = 5a. xz = 6a + 24.
As a result, we need to substitute into the equation and then solve for a.
xz = xy + yz
6a + 24 = 7a + 5a
12a = 6a + 24
6a = 24
a = 24/6
a = 4.
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Step-by-step explanation:
A= πr^2
r = √(A/π)
r = √(676π/π)
r = 26
C = 2πr
52π
= 163.36
Answer:
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