$\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{31em}{0.25pt}\\\\ f(x)= \qquad \begin{cases} x_1=1\\ x_2=3 \end{cases}\implies \cfrac{f(3)-f(1)}{3-1}\implies \cfrac{(5)-(-1)}{3-1} \\\\\\ \cfrac{5+1}{2}\implies \cfrac{6}{2}\implies 3$

4 0

3 years ago

Given that P = (-4, 11) and Q = (-5, 8), find the component form and magnitude of vector QP

Svetach [21]

The given points are
P = (-4,11)
Q = (-5,8)

The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3

The vector QP is
(1,3) or
$\vec{QP} = \hat{i} + 3\hat{j}$

The magnitude of the vector is
√(1² + 3²) = √(10)

Answer:
$\vec{QP} = \hat{i}+3\hat{j} \,\, or \,\, (1,3)$
The magnitude is √(10).

8 0

3 years ago