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3 years ago

Consider the reaction below.

Chemistry

1 answer:

patriot [66]3 years ago

6 0

Answer:

HI and I-

Explanation:

Hello there!

In this case, according to the acid ionization of hydroiodic acid:

$HI+H_2O\rightarrow I^-+H_3O^+$

Now, since the acid, HI, results in the conjugate base, I- and the base, H2O in the conjugate acid, H3O+, it is correct to assert that the acid-conjugate base pair is HI and I-

Best regards!

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SO2(g) + NO2(g) ↔ SO3(g) + NO(g) Kc = 0.33 A reaction mixture contains 0.41 M SO2, 0.14 M NO2, 0.12 M SO3 and 0.14 M NO. Which o

stepladder [879]

Answer:

The reaction will shift in the direction of products.

Explanation:

Step 1: Data given

A reaction mixture contains:

0.41 M SO2

0.14 M NO2

0.12 M SO3

0.14 M NO

Step 2: The balanced equation

O2(g) + NO2(g) ↔ SO3(g) + NO(g) Kc = 0.33

Step 3: Define the direction of the shift of reaction:

When Q<K, there are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.

When Q>K, there are more products than reactants. To decrease the amount of products, the reaction will shift to the left and produce more reactants.

When Q=K, the system is at equilibrium and there is no shift to either the left or the right.

Step 4: Calculate Q

Q = [NO][SO3]/[SO2][NO2]

Q = (0.14 *0.12)/(0.41*0.14)

Q = 0.0168/0.0574

Q = 0.293

Q<Kc

This means there are more reactants than products. Thud, some of the reactants will become products, causing the reaction to shift to the right.

The reaction will shift in the direction of products.

8 0

3 years ago

The particles in liquids and gases show random motion. What does that mean and why does it occur??

SIZIF [17.4K]

Answer:

Liquids and gases show random movements because of potential and kinetic energy.

It happens when heat is applied to the particles and they gain more potential and kinetic energy and move around faster. With gases, they have the most energy.

If anything doesnt make sense, make sure to message me

7 0

3 years ago

Read 2 more answers

Calculate the fraction of lattice sites that are schottky defects for cesium chloride at its melting temperature (645oc). assume

baherus [9]

Answer : 7.87 X $10^{-6}$ .

Explanation : To find the fraction of schottky defects in the given lattice of CsCl,

we use the formula, $\frac{N_{s} }{N}} = exp ( \frac{-Q_{s}}{2KT} )$

on solving with the given values , $Q_{s}= 1.86 eV$ and T as 645 + 273 K and rest are the constants.

$\frac{N_{s} }{N}} = exp ( \frac{-1.86 eV}{2 X (8.62 X 10^{-5}) X (645 +273)} )$

we get the answer as 7.87 X $10^{-6}$ .

6 0

3 years ago

Read 2 more answers

The rate constant for this second‑order reaction is 0.380 M − 1 ⋅ s − 1 0.380 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product

Sati [7]

Answer: 8.38 seconds

Explanation:

Integrated rate law for second order kinetics is given by:

$\frac{1}{a}=kt+\frac{1}{a_0}$