Answer: You can have a loop in a series circuit than a parallel circuit
Explanation: You can have a loop! How is this loop helpful? I don't know, I have no idea how this would be useful. Ah! maybe you can have many things activate sequentially like a lightshow. You can make a series circuit and it will just repeat. You can repeat a lightshow. I don't know what else you can do.
The question is incomplete, the complete question is;
Zinc and sulfur react to form zinc sulfide by the equation shown below. How many grams of ZnS can be formed when 12.0 g of Zn reacts with 6.50 g of S? (Atomic mass: Zn = 65.38, S = 32.06).
Answer:
17.5 g of ZNS
Explanation:
The equation of the reaction is;
Zn(s) + S(s) ------->ZnS(s)
Number of moles of Zn = 12.0/65.38 = 0.18 moles
Number of moles of S = 6.50/32.06 = 0.20 moles
Hence Zn is the limiting reactant
If 1 mole of Zn yields 1 mole of ZnS
Then 0.18 moles of Zn also yields 0.18 moles of ZnS
Mass of ZnS produced = 0.18 moles * 97.44 g/mol = 17.5 g of ZNS
The 2p subshell can hold up to 6 electrons. There are 3 orbitals in 2p subshell. Each orbital can hold only up to 2 electrons. In a xyz plane, each pair of electron is situated in the x-axis, y-axis, and z-axis.
Firstly, we need to convert 3g aspartame into moles aspartame. In order to do this we have to find the molecular mass of aspartame (the total weight of each atom of the molecule combined. This figure can be used to construct a conversion factor so that the grams may be converted into moles. Molecular weights for each atom can be found on any periodic table. Avagadro's number (6.022*10^23) is a constant value that expresses the number of molecules in one mole of a substance.
The molecular weight for aspartame is 294.3 grams per mole.
The process of finding how many atoms of H there are in 3.00g of aspartame would be like this:
1. 3g * 1mol/294.3g = .01mol aspartame (this is converting grams to moles)
2. .01mol * 6.022*10^23 = 6.022*10^21 (This is finding the number of molecules)
3. (6.022*10^21) * 18 = 1.08*10^23
This 3rd calculation is done because in part 2, you calculated the number of molecules of aspartame there were in 3g. In each molecule of aspartame there are 18 hydrogen atoms. So the final answer is:
1.08*10^23 hydrogen atoms.
Answer:
36 KJ of heat are released when 1.0 mole of HBr is formed.
Explanation:
<em>By Hess law,</em>
<em>The heat of any reaction ΔH for a specific reaction is equal to the sum of the heats of reaction for any set of reactions which in sum are equivalent to the overall reaction:</em>
H 2 (g) + Br 2 (g) → 2HBr (g) ΔH = -72 KJ
This is the energy released when 2 moles of HBr is formed from one mole each of H2 and Br2.
Therefore, Heat released for the formation of 1 mol HBr would be half of this.
Hence,
ΔHreq = -36 kJ
36 KJ of heat are released when 1.0 mole of HBr is formed.
