Explanation:
The enzyme 's active site binds to the substrate. Increasing the temperature generally increases the rate of a reaction, but dramatic changes in temperature and pH can denature an enzyme, thereby abolishing its action as a catalyst. ... When an enzyme binds its substrate it forms an enzyme-substrate complex.
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The answer is 44.0095. We assume you are converting between grams CO2 and mole.
Answer:
19.8% of Nitrogen
Explanation:
In the Al(NO₃)₃ there are:
1 atom of Al
3 atoms of N
And 9 atoms of O
The molar mass of Al(NO₃)₃ is:
1 Al * (26.98g/mol) = 26.98g/mol
3 N * (14g/mol) = 42g/mol
9 O * (16g/mol) = 144g/mol
26.98 + 42 + 144 = 212.98g/mol
We can do a conversion using these molar masses to find the mass of nitrogen is the sample, that is:
2.57g * (42g/mol / 212.98g/mol) =
0.51g N
Percent composition of nitrogen is:
0.51g N / 2.57g * 100
= 19.8% of Nitrogen
Answer:
![m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3](https://tex.z-dn.net/?f=m_%7BNa_2CO_3%7D%5E%7Btheoretical%7D%3D6.636gNa_2CO_3)
Explanation:
Hello!
In this case, since the decomposition of sodium hydrogen carbonate is:
![2NaHCO_3(s)\rightarrow Na_2CO_3(s)+H_2O(g)+CO_2(g)](https://tex.z-dn.net/?f=2NaHCO_3%28s%29%5Crightarrow%20Na_2CO_3%28s%29%2BH_2O%28g%29%2BCO_2%28g%29)
Thus, since there is a 2:1 mole ratio between the sodium hydrogen carbonate and sodium carbonate, and the molar masses are 84.01 and 105.99 g/mol respectively, we obtain the following theoretical yield:
![m_{Na_2CO_3}^{theoretical}=10.52gNaHCO_3*\frac{1molNaHCO_3}{84.01gNaHCO_3}*\frac{1molNa_2CO_3}{2molNaHCO_3} *\frac{105.99gNa_2CO_3}{1molNa_2CO_3}\\\\ m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3](https://tex.z-dn.net/?f=m_%7BNa_2CO_3%7D%5E%7Btheoretical%7D%3D10.52gNaHCO_3%2A%5Cfrac%7B1molNaHCO_3%7D%7B84.01gNaHCO_3%7D%2A%5Cfrac%7B1molNa_2CO_3%7D%7B2molNaHCO_3%7D%20%20%2A%5Cfrac%7B105.99gNa_2CO_3%7D%7B1molNa_2CO_3%7D%5C%5C%5C%5C%20m_%7BNa_2CO_3%7D%5E%7Btheoretical%7D%3D6.636gNa_2CO_3)
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