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jeka94
3 years ago
7

g Write a molecular equation for the precipitation reaction that occurs (if any) when the following solutions are mixed. If no r

eaction occurs, write NOREACTION. copper (II) bromide and lead (II) acetate
Chemistry
1 answer:
Mrac [35]3 years ago
8 0

Answer:

CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

Explanation:

We identify the reactants:

CuBr₂ and Pb(CH₃COO)₂

The products will be: Cu(CH₃COO)₂ and PbBr₂

You may know these information:

Salts from acetate are soluble.

Bromide can make solid salts with these cations: Ag⁺, Pb²⁺, Hg₂²⁺, Cu⁺

PbBr₂ is formed, so this will be our precipitate

The equation is:

CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

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A sample of gasoline has a mass of 595.0 lb and a volume of 14.0 ft^3. What is its specific gravity?
Sedbober [7]

Explanation:

The given data is as follows.

            mass of gasoline = 595.0 lb

            volume of gasoline = 14.0 ft^{3}

As it is known that density is the amount of mass of a substance divided by its volume.

So, density of gasoline will be as follows.

                Density = \frac{mass}{volume}

                              = \frac{595.0 lb}{14.0 ft^{3}}

                              = 42.5 lb/ft^{3}

As, 1 lb = 0.4536 kg and 1 ft = 0.3048 m. Now, putting these values into the above equation (1) as follows.

                       Density = 42.5 lb/ft^{3}

                                     = 42.5 \times \frac{0.4536 kg}{(0.3048 m)^{3}}

                                     = 680.792 kg/m^{3}    

                                     = 680.8 kg/m^{3} (approx)

Density of water is 1000 kg/m^{3}. To measure specific gravity of gasoline, the formula will be as follows.

               specific gravity of gasoline = \frac{\text{density of gasoline}}{\text{density of water}}    

                                         = \frac{680.8 kg/m^{3}}{1000 kg/m^{3}}

                                         = 0.681

Thus, we can conclude that the specific gravity of gasoline is 0.681.

4 0
4 years ago
What are the 5 forms of energy
stepladder [879]
<span>mechanical energy, thermal energy, nuclear energy, chemical energy, electromagnetic energy </span>
7 0
3 years ago
Why are redox reactions often written as net ionic equations?
Scorpion4ik [409]

Answer:

A. To focus on only those ions that form the precipitate

Explanation:

Net ionic equations cancel out the ions that appear on both sides of the reaction because they essentially don't participate in the reaction. This is very useful when dealing with redox reactions because are complicated enough without spectator ions being in the way, so they help focus on those ions that actually form the precipitate.

Key Terms

  • Spectator Ions: an ion that does not take part in the chemical reaction.
  • Net ionic equations: a equation where  ions that appear on both sides are canceled out.
  • Redox reaction: an oxidation-reduction reaction.
3 0
3 years ago
Consider the lewis structures for the compound so3 and the polyatomic ions so32- and so42-. which of these must exist as a set o
luda_lava [24]
It is a multiply question but your didn't include the choice in this question but the answer in this question is only so3 or s03 only. So3 is the only one that must exist as a set of resonance structures. So3 may be refer to a sulfur trioxide wich means a chemical compound of both trioxide and sulfur.
6 0
3 years ago
An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure and temperature were 94.0mL,
xeze [42]

Answer: The original volume in liters was 0.0707L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.85 atm

P_2 = final pressure of gas = 456 mm Hg = 0.60 atm   (760mmHg=1atm)

V_1 = initial volume of gas = ?

V_2 = final volume of gas = 94.0 ml

T_1 = initial temperature of gas = 66^oC=273+66=339K

T_2 = final temperature of gas = 113^oF=318K  (32^0F=273K)

Now put all the given values in the above equation, we get:

\frac{0.85\times V_1}{339}=\frac{0.60\times 94.0}{318}

V_1=70.7ml=0.0707L   (1L=1000ml)

Thus the original volume in liters was 0.0707L

8 0
3 years ago
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