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3 years ago

Work out the value of x

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

8 0

Answer:

x =60

Step-by-step explanation:

pashok25 [27]3 years ago

5 0

Answer:

X = 60°

Step-by-step explanation:

You can see that 60° on the other side is also 60°

So, X = 60°

Hope this helps! :)

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Solve for x: 3(x-5)+4x-2=4

zysi [14]

Answer:

x = 3

Step-by-step explanation:

3(x−5)+4x−2=4

Step 1: Simplify both sides of the equation.

3(x−5)+4x−2=4

(3)(x)+(3)(−5)+4x+−2=4(Distribute)

3x+−15+4x+−2=4

(3x+4x)+(−15+−2)=4(Combine Like Terms)

7x+−17=4

7x−17=4

Step 2: Add 17 to both sides.

7x−17+17=4+17

7x=21

Step 3: Divide both sides by 7.

x=3

3 0

3 years ago

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Margarita [4]

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3 0

3 years ago

Read 2 more answers

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

Find a formula for the nth term of the arithmetic sequence a1=-17 a2=-12 a3=-7 a4=-2

MAVERICK [17]

Answer:

Step-by-step explanation:

Recursive formula

a1 = -17

a^n = a^n-1 + 5

Explicit formula:

a^n = -17 + (n-1) * 5

3 0

3 years ago

Find the measure of the angles indicated

GalinKa [24]

Both angles have a measure of 125°.

<h3>How to find the measure of the angles?</h3>

Assuming the two horizontal lines are parallel, we know that the measure of the two indicated angles must be the same one.

Then:

-1 + 14x = 12x + 17

Now we need to solve this for x:

14x - 12x = 17 + 1

2x = 18

x =18/2 = 9

Now that we know the value of x we can replace it in any of the expressions for the angles:

-1 + 14*9 = 125°

Both angles have a measure of 125°.

If you want to learn more about angles:

brainly.com/question/25716982

#SPJ1

8 0

2 years ago