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Bess [88]
3 years ago
9

A 20000 kg railroad car is rolling at 1.00 m/s when a 1000 kg load of gravel is suddenly dropped in. part a what is the car's sp

eed just after the gravel is loaded?
Physics
1 answer:
Talja [164]3 years ago
8 0
Using conservation of energy and momentum we get m1*v1=(m1+m2)*v2 so rearranging for v2 and plugging the given values in we get:
(200000kg*1.00m/s)/(21000kg)=.952m/s
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What is the force of a 13kg ball that has been dropped and has fallen for 1 second?
ankoles [38]

Answer:

127.4 newtons

Explanation:

Assuming g = 9.8:

F = ma = 13(9.8) = 127.4 N

6 0
3 years ago
A 0.005 kg bullet is travelling horizontally at a velocity of 250 m/s when it strikes a wooden block of mass 12 kg on a table at
Verdich [7]
Use the conservation of momentum formula: m1v1 + m2v2 = v(m1 + m2)

(0.005kg)(250m/s) + (12kg)(0m/s) = v(0.005kg + 12kg)

v = ((0.005kg)(250m/s)) / (0.005kg + 12kg)

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6 0
4 years ago
What is number 30,31 in this picture?
Maslowich
On question 30, that is a displacement- time graph (DT). On this type of graph the gradient is equal to the velocity. B has the steepest gradient, then A and finally C

Now velocity is a vector quantity so it has a direction and speed ( speed doesn't have a fixed direction.)

on the DT graph im going to assume that movement B is a positive velocity with A and C being negative. 
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Q31, The same type of graph is present, by looking at the gradients we can rank the largest and smallest velocities- speeds in the case of the question. 
i'll skip my working out as its the same as before:

C, B, A and then D

the same idea as on Q30 applies to Q31 part b, 

D,C,B then A 
6 0
3 years ago
List three devices that use electric current from batteries and three that use regular house current.
Bond [772]
Charger
counsels
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Fan
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4 0
4 years ago
Please help on questions D AND E and please show working out as well so I can understand better thank you only QUESTIONS D AND E
tester [92]

Answer:

d. 87,500 J

e. 49,600 J

Explanation:

The total energy is the heat absorbed by the copper plus the heat absorbed by the water.

d)

E = m₁C₁ΔT + m₂C₂ΔT

E = (1 kg) (390 J/kg/°C) (10 °C) + (2 kg) (4180 J/kg/°C) (10 °C)

E = 87,500 J

e)

E = m₁C₁ΔT + m₂C₂ΔT

E = (2 kg) (390 J/kg/°C) (10 °C) + (1 kg) (4180 J/kg/°C) (10 °C)

E = 49,600 J

5 0
3 years ago
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