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Bess [88]
3 years ago
9

A 20000 kg railroad car is rolling at 1.00 m/s when a 1000 kg load of gravel is suddenly dropped in. part a what is the car's sp

eed just after the gravel is loaded?
Physics
1 answer:
Talja [164]3 years ago
8 0
Using conservation of energy and momentum we get m1*v1=(m1+m2)*v2 so rearranging for v2 and plugging the given values in we get:
(200000kg*1.00m/s)/(21000kg)=.952m/s
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A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point) 28 kg⋅m/s 28 kilo
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The impulse of the boxers punch is 28 kgm/s.

The given parameters;

  • <em>applied force by the boxer, F = 1400 N</em>
  • <em>time of force action, t = 0.02 s</em>

<em />

The impulse of the boxers punch is calculated as follows;

J = Ft

where;

  • <em>F is the applied force (N)</em>
  • <em>t is the time of force action (s)</em>

The magnitude of the impulse is calculated as follows;

J = 1400 \times 0.02 \\\\J = 28 \ kg m/s

Thus, the impulse of the boxers punch is 28 kgm/s.

Learn more about impulse here: brainly.com/question/25700778

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