3 years ago

Help Plaeseeeeeeee!

Physics

2 answers:

pogonyaev3 years ago

6 0

Answer:

golf ball on the grass

Explanation: i took the test

vladimir2022 [97]3 years ago

3 0

Answer:

golf all on grass covered hill in sunlight

Explanation:

someone pouring/spinning top has a lot of motion going on. a roller coaster has force acting on it which increases the motion.

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Are we really real or are we all an allusion?Do you believe in past lives?How do you think you died in past life?

OLEGan [10]

Answer:

I don't even know

Explanation:

Shower thoughts

8 0

2 years ago

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Take a close look at the energy transfers and transformations shown in the above diagram. Which type of energy is transformed in

labwork [276]

Kinetic Energy

How to calculate

Kinetic energy is given by K.E.

$\\ \sf\longmapsto K.E=\dfrac{1}{2}mv^2$

Where

m is denoted to mass
v is denoted to velocity

4 0

3 years ago

A racecar experiences a centripetal acceleration of 36.0 m/s2 as it travels at a constant speed of 27.0 m/s along a circular arc

alexdok [17]

Answer:

20.25 m

Explanation:

Centripetal acceleration is given by; the square of the velocity, divided by the radius of the circular path.

That is;

ac = v²/r

Where; ac = acceleration, centripetal, m/s², v is the velocity, m/s and r is the radius, m

Therefore;

r = v²/ac

= 27²/36

= 20.25 m

Hence the radius is 20.25 meters

5 0

3 years ago

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Bromine, a liquid at room temperature, has a boiling point

lukranit [14]

Yes it does ! The so-called "boiling point" is the temperature at which Bromine liquid can change state and become Bromine vapor, if enough additional thermal energy is provided. The boiling point is higher than room temperature.

3 0

3 years ago

A small metal object is tied to the end of a string and whirled round a circular path of radius 30cm. The object makes 20 oscill

LUCKY_DIMON [66]

Answer:

(i) The angular speed of the small metal object is 25.133 rad/s

(ii) The linear speed of the small metal object is 7.54 m/s.

Explanation:

Given;

radius of the circular path, r = 30 cm = 0.3 m

number of revolutions, n = 20

time of motion, t = 5 s

(i) The angular speed of the small metal object is calculated as;

$\omega = \frac{20 \ rev}{5 \ s} \times \frac{2 \pi \ rad}{1 \ rev} = \frac{40\pi \ rad}{5 \ s} = 8\pi \ rad/s = 25.133 \ rad/s$

(ii) The linear speed of the small metal object is calculated as;

$v = \omega r\\\\v = 25.133 \ rad/s \ \times \ 0.3 \ m\\\\v = 7.54 \ m/s$

6 0

3 years ago