Data:
n (Wave node)
V (Wave belly)
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
Wire 2 → 2º Harmonic → n = 2
Wire 1 → 1º Harmonic or Fundamental rope → n = 1
If, We have:
V = 42L
Soon:
Answer:
<span>The fundamental frequency of the string:
</span>
21 Hz
To solve this problem we will apply the laws of Mersenne. Mersenne's laws are laws describing the frequency of oscillation of a stretched string or monochord, useful in musical tuning and musical instrument construction. This law tells us that the velocity in a string is directly proportional to the root of the applied tension, and inversely proportional to the root of the linear density, that is,
Here,
v = Velocity
= Linear density (Mass per unit length)
T = Tension
Rearranging to find the Period we have that
As we know that speed is equivalent to displacement in a unit of time, we will have to
Therefore the tension is 5.54N
Answer:
1.) Covering the ceiling and walls with soft perforated boards
2.) Hanging curtains round the hall
3.) Having more opening in the wall.
Explanation:
This is due to what we called Reverberation due to poor acoustic properties.
Reverberation can be reduced by;
1.) Covering the ceiling and walls with soft perforated boards
2.) Hanging curtains round the hall
3.) Having more opening in the wall.
The solution would be like this for this specific problem:
F = (G Me Mo) / Re^2
F / Mo = (G Me) / Re^2
G = gravitational constant
= 6.67384 * 10^-11 m3 kg-1 s-2
Me = 5.972 * 10^24 kg
Re^2 = (6.38 * 10^6)^2 m^2
= 40.7044 * 10^12 m^2 = 4.07044 * 10^13 m^2
G Me / Re^2 = (6.67384 * 10-11
* 5.972 * 10^24) / 4.0704 * 10^13 = 9.7196 m/s^2
9.7196 m/s^2 = acceleration
due to Earth’s gravity
Therefore, the value of the composite constant (Gme / r^2e) that is to be
multiplied by the mass of the object mo in the equation above is 9.7196
m/s^2.
