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anastassius [24]
3 years ago
14

If you want to study how energetic waves affect matter, you should study waves with a _______.

Physics
1 answer:
tankabanditka [31]3 years ago
4 0

Higher Frequency and shorter wavelength. The energy of light waves increases when there is an increasing frequency and a higher frequency means there are shorter wavelengths. The equation lambda=c/f where lambda is wavelength and f is frequency and c is the speed of the wave.

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Suppose you want to determine the resistance of a resistor that is nominally 100 . You should be able to apply 10 V across the r
Butoxors [25]

Answer:

a) For y = 102 mA, R = 98.039 ohms

For y = 97 mA, R = 103.09 ohms

b) Check explanatios for b

Explanation:

Applied voltage, V = 10 V

For the first measurement, current y_{1} = 102 mA = 0.102 A

According to ohm's law, V = IR

R = V/I

Here, I = y_{1}

R = \frac{V}{y_{1} } \\R = \frac{10}{0.102} \\R = 98.039 ohms

For the second measurement, current y_{2} = 97 mA = 0.097 A

R = \frac{V}{y_{2} }

R = \frac{10}{0.097} \\R = 103 .09 ohms

b) y = \left[\begin{array}{ccc}y_{1} &y_{2} \end{array}\right] ^{T}

y = \left[\begin{array}{ccc}y_{1} \\y_{2} \end{array}\right]

y = \left[\begin{array}{ccc}102*10^{-3} \\97*10^{-3}  \end{array}\right]

A linear equation is of the form y = Gx

The nominal value of the resistance = 100 ohms

x = \left[\begin{array}{ccc}100\end{array}\right]

\left[\begin{array}{ccc}102*10^{-3} \\97*10^{-3}  \end{array}\right] =  \left[\begin{array}{ccc}G_{1} \\G_{2}  \end{array}\right] \left[\begin{array}{ccc}100\end{array}\right]\\\left[\begin{array}{ccc}G_{1} \\G_{2}  \end{array}\right] =  \left[\begin{array}{ccc}102*10^{-5} \\97*10^{-5}  \end{array}\right]

3 0
3 years ago
A complete circuit is often referred to as a(n) _______ circuit
aivan3 [116]

Answer:

Complete Circuit

Explanation:

A circuit is defined as a completed path for voltage to flow from a source of voltage through a load and back to the source. A complete circuit or path is often referred to as a(n) ? circuit. Before current can flow in a circuit, the circuit must be closed. 100% right

4 0
3 years ago
A specialist who treats skin conditions and diseases is a
s2008m [1.1K]
A doctor who specializes in the area of skin health is a dermatologist
5 0
3 years ago
A group of students performed a compression experiment where they placed weights on top of a cylinder of material and measured t
kolbaska11 [484]

The material that the cylinder is made from is Butyl Rubber.

<h3>What is Young's modulus?</h3>

Young's modulus, or the modulus of elasticity in tension or compression, is a mechanical property that measures the tensile or compressive strength of a solid material when a force is applied to it.

<h3>Area of the cylinder</h3>

A = πr²

A = \pi \times (0.02)^2 = 0.00126 \ m^2

<h3>Young's modulus of the cylinder</h3>

E = \frac{stress}{strain} \\\\E = \frac{F/A}{e/l} \\\\E = \frac{Fl}{Ae} \\\\

Where;

  • e is extension

When 5 kg mass is applied, the extension = 10 cm - 9.61 cm = 0.39 cm = 0.0039 m.

E = \frac{(5\times 9.8) \times 0.1}{0.00126 \times 0.0039} \\\\E = 9.97 \times 10^5 \ N/m^2\\\\E = 0.000997 \times 10^9 \ N/m^2\\\\E = 0.000997 \ GPa\\\\E \approx 0.001 \ GPa

When the mass is 50 kg,

extension = 10 cm - 7.73 cm = 2.27 cm = 0.0227 m

E = \frac{(50\times 9.8) \times 0.1}{0.00126 \times 0.0227} \\\\E = 1.7 \times 10^6 \ N/m^2\\\\E = 0.0017 \times 10^9 \ N/m^2\\\\E = 0.0017 \ GPa\\\\E \approx 0.002 \ GPa

The Young's modulus is between 0.001 GPa  to 0.002 GPa

Thus, the material that the cylinder is made from is Butyl Rubber.

Learn more about Young's modulus here: brainly.com/question/6864866

3 0
3 years ago
Read 2 more answers
When energy changes form, energy is...<br><br>A) lost.<br>B) created.<br>C) not lost or created.
devlian [24]

Answer:

C

Explanation:

Energy is neither created or destroyed, but it can change forms...

6 0
3 years ago
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