Answer:
C. 54,000 m^2
Step-by-step explanation:
2 sides + 2 more sides
2(150x100) + 2(150x80)
30000 + 24000
54000m^2
Answer and Step-by-step explanation:
A. 4 inches: An object that's 4 inches is about 2.54 centimeters or 25.4 millimeters. An business envelope is typically about 4 inches by 9 inches for example.
B. 6 feet: A 6 feet object is quite big when compared to just 4 inches. A feet is 12 inches hence 6 feet is 72 inches. A very tall human being is typically 6 feet.
C. 1 meter: A meter is about 39.37 inches hence it is quite big when compared to a feet. A baseball bat is one meter long.
D. 5 yards: A yard is 36 inches hence a bit smaller than a meter. A trampoline could be 5 yards for example
E. 6 centimeters: one centimeter is 0.394 inches hence smaller than an inch. A 6 centimeters object for example is pencil for writing.
F. 2 millimeters: a millimeter is 0.0394 inches hence smaller than a centimeter and an inch. An orange seed could be 2 millimeters long
G. 3 kilometers: one kilometer is 39370.079 inches hence a kilometer is bigger than inches, meter, feet, yards, centimeters, millimeters. A very big tree could be 3 kilometers long
Hello from MrBillDoesMath!
Answer:
x = 2 and 10
Discussion:
Approach 1:
20 = (-10)*(-2) and (-10) + (-2) = -12 the coefficients of the polynomial. Hence
x^2 -12x + 20 = ( x- 2) * ( x-10)
Approach 2:
From the quadratic formula ( a = 1, b = -12, c = 20)
x = ( -(-12) +\- sqrt( ((-12)^2 - 4*1*20) ) / (2 * 1)
= ( 12 +\- sqrt( 144-80) ) /2
= (12 +\- sqrt(64) ) /2
= (12 +\- 8 ) /2
x = ( 12 + 8) /2 = 20/2 = 10
or
x = ( 12 - 8)/ 2 = 4/2 = 2
Thank you,
MrB
Answer:
x≈ 3.2056
Step-by-step explanation:
Set both sides by log. Then, solve for x.
1. 14^(x + 1) = 36
(x + 1)log(14) = log(36)
x + 1 = log(36)/log(14) . . . Divide both sides by log(14)
x = log(36)/log(14) - 1 . . . . Subtract both sides by 1.
x ≈ 0.3579 . . . . . . . . . . . .Use calculator to simplify the expression.
Note that the second problem is similar to the first.
2. 12^(y - 2) = 20
(y - 2)log(12) = log(20)
y - 2 = log(20)/log(12)
y = log(20)/log(12) + 2
y ≈ 3.2056
Degree days are the difference between the daily temperature mean, (high temperature plus low temperature divided by two) and 65°F. 65°F because we assume that at this temperature we do not need cooling or heating.
In our case the daily mean temperature is 83°F and X is the number of cooling-degree days.
X=83-65
X=18
