Answer:
c. 29 J
Explanation:
Step 1: Given data
- Specific heat capacity of Pb (c): 0.13 J/g.K (= 0.13 J/g.°C)
- Initial temperature: 22 °C
Step 2: Calculate the temperature change
ΔT = 37 °C - 22 °C = 15 °C
Step 3: Calculate the heat (Q) required to raise the temperature of the lead piece
We will use the following expression.
Q = c × m × ΔT
Q = 0.13 J/g.°C × 15 g × 15 °C = 29 J
Answer:
2KClO3--------->2KCl + 3O2
density is the kilogram per cubic metre means mass divided by volume.
mathmatically= density= mass/ volume
rough = m/v
