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aivan3 [116]
3 years ago
15

Mina is attending cooking school, where she prepares different mixtures of ingredients. She works with both homogenous and heter

ogeneous mixtures. Today she is using honey and salsa. What kinds of mixtures are these ingredients?
Chemistry
1 answer:
rodikova [14]3 years ago
3 0

Answer:

Honey is an homogeneous mixture

Salsa is an heterogeneous mixture

Explanation:

Honey is a sweet uniformly colored liquid that can be of a dark variety or of clear golden color. Honey is made in nature by bees from flower nectar and is used as a food additive or sweetener

Honey is a homogeneous mixture because the concentration of the components of honey are uniformly distributed throughout the mixture. Every portion has the same concentration of components

Salsa is a sauce made by mixing chopped tomatoes, onions, chilies, lime juice and seasoning and therefore consists of both solid and liquid components mixed in varying proportion such that part will have continuous  that comes in between different types of solid and no two parts have exactly the same composition

Therefore, salsa is an heterogenous liquid.

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The ammonia molecule in the diagram has the observed bond orientation because ...
aivan3 [116]

Answer:

  • Nitrogen has four pairs of electrons: 3 bonds and 1 lone pair in the valence shell;
  • Electrons repel one another based on the VSEPR theory;
  • Nitrogen has a total of 7 protons (its atomic number is 7) in its nucleus.

Explanation:

The shape and the bond orientation of molecules and ions are both explained by the valences shell electron pair repulsion theory (VSEPR).

Ammonia, NH_3, is a molecule which contains three N-H bonds, as well as one lone pair on nitrogen. According to the VSEPR theory, molecules try to acquire a shape which would minimize the repulsion exhibited by the electron clouds present, that is, between the bonding (shared in a bond) and non-bonding (lone pair) electrons.

In VSEPR, our main step is to calculate the steric number, this is the sum of the number of bonds (ignoring the multiplicity of any bond) and the lone pairs on a central atom. In ammonia, we have 3 bonds and 1 lone pair, totaling to a steric number of 4. A steric number of 4 without any lone pairs on a central atom and just bonds would yield a tetrahedral shape with bond angles of 109.5^o.

Now, in this case, since we have a lone pair instead of a bond, it is repelling stronger decreasing the bond angles to about 107^o.

The greater the number of lone pairs, the lower the angle becomes.

To summarize:

  • Nitrogen has four pairs of electrons: 3 bonds and 1 lone pair in the valence shell;
  • Electrons repel one another based on the VSEPR theory;
  • Nitrogen has a total of 7 protons (its atomic number is 7) in its nucleus.
3 0
3 years ago
Name 2 parts of a microscope
Airida [17]
Two parts are stage and coarse focus
6 0
3 years ago
What is nuclear fission
swat32
Nuclear fission is the process of which a large nucleus splits into two smaller nuclei with the release of energy and neutron. In simpler words, nuclear fission is the process in which a nucleus is split into two smaller fragments or pieces (nuclei) and so energy and neutrons are released. The resulting pieces of this fission process have less combined mass than the original piece (nucleus) and the missing was is converted into nuclear energy.
5 0
3 years ago
Read 2 more answers
PLEASE HELP I NEED IT!!!!!
galina1969 [7]
Answer:
Molarity = 2.3 M

Explanation:
Molarity can be calculated using the following rule:
Molarity = number of moles of solute / volume of solution

1- getting the number of moles:
We are given that:
mass of solute = 105.96 grams
From the periodic table:
atomic mass of carbon = 12 grams
atomic mass of hydrogen = 1 gram
atomic mass of oxygen = 16 grams
Therefore:
molar mass of C2H6O = 2(12) + 6(1) + 16 = 46 grams
Now, we can get the number of moles as follows:
number of moles = mass / molar mass = 105.96 / 46 = 2.3 moles

2- The volume of solution is given = 1 liter

3- getting the molarity:
molarity = number of moles of solute / volume of solution
molarity = 2.3 / 1
molarity = 2.3 M

Hope this helps :)
8 0
3 years ago
The activation energy of a reaction is 56.9 kj/mol and the frequency factor is 1.5×1011/s. Part a calculate the rate constant of
Vanyuwa [196]

We will use Arrehenius equation

lnK = lnA  -( Ea / RT)

R = gas constant = 8.314 J / mol K

T = temperature = 25 C = 298 K

A = frequency factor

ln A = ln (1.5×10 ^11) = 25.73

Ea = activation energy = 56.9 kj/mol = 56900 J / mol

lnK = 25.73 - (56900 / 8.314 X 298) = 2.76

Taking antilog

K = 15.8



5 0
3 years ago
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