Answer:
5 m/s
Explanation:
Horizontal distance traveled, x = 2 m
vertical distance traveled, y = 4/5 m
Let the speed of cup as it leaves the counter is v and it takes time t to hit the ground.
Use second equation of motion in vertical direction
Here acceleration in vertical direction is 9.8 m/s^2.
So,
t = 0.4 second
Now in horizontal direction the acceleration in zero.
Horizontal distance = horizontal velocity x time
x = v t
2 = v (0.4)
v = 5 m/s
Thus, the horizontal velocity of cup as it leaves the counter is 5 m/s.
According to Archimedes Principle, Buoyant Force is equivalent to the displaced<span> amount of </span><span>fluid, So, Larger the amount of water displaced, more the Buoyant force will be.
In short, Object 3 would have the largest Buoyant Force
Hope this helps!</span>
The angular momentum of a rotation object is the product of its moment of inertia and its angular velocity:
L = Iω
L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Apply the conservation of angular momentum. The total angular momentum before disks A and B are joined is:
L_{before} = (3.3)(6.6) + B(-9.3)
L_{before} = -9.3B+21.78
where B is the moment of inertia of disk B.
The total angular momentum after the disks are joined is:
L_{after} = (3.3+B)(-2.1)
L_{after} = -2.1B-6.93
L_{before} = L_{after}
-9.3B + 21.78 = -2.1B - 6.93
B = 4.0kg·m²
The moment of inertia of disk B is 4.0kg·m²
Answer:
The answer is B. Without a college education, workers will actually lose money in the long run.
Explanation:
Just got it right on the assignment
False because they can be really big
sorry for the explanation on how bad it was LOL
