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3 years ago

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Chemistry

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Allisa [31]3 years ago

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Answer:

बालकेभ्य।

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How is a hydrogen bond different from an ionic or covalent bond?

o-na [289]

Answer:

Hydrogen bonds are totally different to both covalent bonds and ionic bonds. Hydrogen bonds are intermolecular bonds, that means they occur in between two molecules. ... When H atom is close to O,F, N atoms those atoms can attract H atoms electrons temporarily, thus making a weak bond.

Explanation:

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4 years ago

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Each orbit surrounding an atom is allowed _____. only 2 electrons only 8 electrons an unlimited number of electrons a limited nu

PIT_PIT [208]

Each orbit surrounding an atom is allowed A LIMITED NUMBER OF ELECTRONS.

The number of orbit that an atom has is determined by its atomic number, the higher the atomic number the higher the number of orbit in the atom and each orbit has different energy level. Each orbit can only take fixed number of electron. The first shell can only take two electrons while the subsequent shells can only take eight electrons. When an orbit has taken the highest number of electron possible, the remaining electrons are moved to the next shell.

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3 years ago

Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic centimeter for a silver-gold

Sonja [21]

Answer:

The Number of gold atoms are = $N_{Au}=1.81718*10^{22}\ atoms/cm^3$

Explanation:

The formula we are going to use is:

$N_{Au}=\frac{N_A*C_{Au}}{{\frac{C_{Au}A_{Au} }{\rho_{Au}}}+\frac{A_{Au}}{\rho_{Ag}}(100-C_{Au})}$

Where:

$N_{Au}$ are number of gold atoms.

$N_A$ is Avogadro Number.

$C_{Au}$ is the amount of gold.

$A_{Au}$ is the atomic weight of gold.

$\rho_{Au}$ is the density of gold.

$\rho_{Ag}$ is the density of silver.

$C_{Ag}$ is the amount of silver.

$N_{Au}=\frac{6.023*10^{23}*45\%wt}{\frac{45\%wt*196.97}{19.32}+\frac{196.97}{10.49}(100-45\%wt)}\\ N_{Au}=1.81718*10^{22}\ atoms/cm^3$

The Number of gold atoms are = $N_{Au}=1.81718*10^{22}\ atoms/cm^3$

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4 years ago

A bicycle tire has a volume of 1.0 l at 22°c. if the temperature of the tire is increased to 52°c, what is the resulting volume

tresset_1 [31]

The relationship between the volume, temperature, and pressure of the gas can be given by Charles law. The volume of the tire is 1.1 L.

<h3>What is Charle's law?</h3>

According to Charles's law, the volume is directly proportional to the temperature of the gas at a constant pressure.

Charle's law can be shown as,

$\rm \dfrac{V_{1}}{T_{1}} = \rm \dfrac{V_{2}}{T_{2}}$

Given,

Initial volume = 1.0 L

Initial temperature = 295 K

Final volume = ?

Final temperature = 325 K

Substituting values in the above equation the final volume can be calculated as:

$\begin{aligned}\rm V_{2} &= \rm \dfrac{V_{1}T_{2}}{T_{1}}\\\\&= \dfrac{ 1 \times 325}{295}\\\\&= 1.1\;\rm L\end{aligned}$

Therefore, the final resulting volume of the tire is 1.1 L.

Learn more about Charle's law here:

brainly.com/question/26849359

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3 years ago

1-Convert the following to moles:<br> 1.5 X 10^23 atoms of Carbon

marin [14]

Answer:

0.249087

Explanation:

1.5 x 10^23 atoms x 1 mole / 6. 022 x 10^23 atoms

= 0.249087

3 0

3 years ago