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lukranit [14]
3 years ago
12

1. फल

Chemistry
1 answer:
Allisa [31]3 years ago
5 0

Answer:

बालकेभ्य।

2 गुरुभि :

3 •••••

4 कवीन।

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Rationalize the difference in boiling points between the members of the following pairs of substances. Part APart complete HF (2
Mrrafil [7]

Answer:

HF has the higher boiling point because HF molecules are more polar. Part B: CHBr3 molecules possess stronger intermolecular interaction due to higher molar mass than CHCl3

Explanation:

Fluorine is more electronegative than chlorine. This implies that HF is more polar and possess stronger hydrogen bonds than HCl molecules.

In part B, the magnitude of dispersion forces depend on molar mass, the greater the molar mass, the greater the magnitude of dispersion forces between molecules, hence CHBr3 has a greater boiling point than CHCl3

4 0
3 years ago
oxygen is a common oxidizing agent in nature. what change in the oxidation number of oxygen must occur if it is to be an oxidizi
Minchanka [31]

Answer is: the oxidation number of oxygen must decrease.

Oxidizing agent is element (substance) that gain electrons in chemical reaction.

For example, balanced chemical reaction: C + O₂ → CO₂.

Oxygen change oxidation number from 0 to oxidation number -2 (reduction) and carbon change from 0 to +4 (oxidation)

6 0
3 years ago
Which examples of science rather than pseudoscience
Sladkaya [172]

Here's three i can name off the top of my head.

Physics , Chemistry  and Biology are all real types of science.

7 0
3 years ago
If 89.6 joules of heat 20.0 grams of iron from 30.0 C to 40.0 C, what is the specific heat of the iron in J/g.C?
atroni [7]

Answer:

 

H = m c ΔT  

89.6 J = (20.0 g) × c × (40.0 - 30.0)°C  

Specific heat of iron, c = 89.6 / [20.0 × (40.0 - 30.0)] J/(g°C) = 0.448 J/(g°C)

4 0
3 years ago
please look at the attached image i have to finish this entire unit by midnight and im stuck on this problem
djyliett [7]
\text{H}_{2(g)}\text{ + CO}_{2(g)}\text{ }\rightleftarrows\text{ H}_2\text{O}_{(g)}\text{ + CO}_{(g)}

The reaction is balanced

The equilibrium constant is defined as the concentration ratio of the products and reactants. They are not considered pure solids and liquids.

\text{ K}_{eq}=\frac{\lbrack\text{CO}\rbrack\lbrack\text{ H}_2\text{O}\rbrack}{\lbrack\text{ H}_2\rbrack\lbrack\text{ CO}_2\rbrack}

So the answer is option B.

4 0
1 year ago
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