Ok so we'll go ahead and solve for y first - we just need to get it alone on one side of the equal sign
Step 1: subtract 2x from each side
2x - 7y - 2x = 19 - 2x
This cancels out the 2x on the left, giving us
-7y = 19 - 2x
Step 2: divide both sides by -7
= 
+ 
This gives us
y = -19/7 + 2x/7
That should be your answer for the first question. Now solving the next parts are easy. All you need to do is plug in x.
When x = -3
y = -19/7 + 2x/7
y = -19/7 + 2(-3)/7
y = -19/7 - 6/7
y = -25/7
When x = 0
y = -19/7 + 2x/7
y = -19/7 + 2(0)/7
y = -19/7
When x = 3
y = -19/7 + 2x/7
y = -19/7 + 2(3)/7
y = -19/7 + 6/7
y = -13/7
Hope that helps! Feel free to ask if I can help with anything else :)
Direct Variation equation: y=kx, k=y/x
42/14=3
k=3
y=3x
y=3(90)
y=270
<u>Given</u>:
Given that ABC is a right triangle.
The length of AB is 7 units.
The measure of ∠A is 65°
We need to determine the length of AC
<u>Length of AC:</u>
The length of AC can be determined using the trigonometric ratio.
Thus, we have;
Where the value of 
is 65° and the side adjacent to the angle is AC and the side hypotenuse to the angle is AB.
Substituting the values, we have;
Substituting AB = 7, we have;
Multiplying both sides by 7, we get;
Rounding off to the nearest hundredth, we get;
Thus, the length of AC is 2.96 units.
Answer:
We conclude that segment QR is the shortest.
Hence, option B is true.
Step-by-step explanation:
First, we need to determine the missing angle m∠R
Given the triangle Δ∠PQR
m∠P = 48°
m∠Q = 83°
m∠R = ?
We know the sum of angles of a triangle is 180°.
m∠P+m∠Q+m∠R = 180°
48°+83°+m∠R=180°
m∠R = 180° - 48° - 83°
m∠R = 49°
Thus, the value of m∠R = 49°
We know that the longest side in a triangle is opposite the largest angle, and the shortest side is opposite the smallest angle.
Here,
m∠P = 48° is the shortest angle.
As the side QR segment is opposite the smallest angle i.e. m∠P = 48°
Therefore, we conclude that segment QR is the shortest.
Hence, option B is true.
Answer:
point of intercept
Step-by-step explanation:
measure x and y axis to see where they cross
