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wolverine [178]
4 years ago
5

. Explain how habitat fragmentation and biomagnification of pollutants affects wildlife.

Physics
1 answer:
Anuta_ua [19.1K]4 years ago
8 0

Answer:

Reduction in the total area of the habitat

Decrease of the interior

Isolation of one habitat fragment from other areas of habitat

Breaking up of one patch of habitat into several smaller patches

A Decrease in the average size of each patch of habitat

Explanation:

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Why is it when you step out of the shower in a warm bathroom you start to shiver
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That is because you did not adjust to that temperature. You changed your temperature suddenly, which made you shiver. <span />
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A gas occupies 2 m^3 at 27°C at a pressure of 1 atmosphere. At a pressure of 2 atmospheres it occupies a volume of 1 m^2. What i
diamong [38]

Answer:

27°C

Explanation:

We'll begin by converting 27 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 27 °C

Initial temperature (T₁) = 27 °C + 273

Initial temperature (T₁) = 300 K

Next, we shall determine the final temperature of the gas. This can be obtained as follow:

Initial volume (V₁) = 2 m³

Initial temperature (T₁) = 300 K

Initial pressure (P₁) = 1 atm

Final pressure (P₂) = 2 atm

Final volume (V₂) = 1 m³

Final temperature (T₂) =?

P₁V₁/T₁ = P₂V₂/T₂

1 × 2 / 300 = 2 × 1 / T₂

2/300 = 2/T₂

1/150 = 2/T₂

Cross multiply

T₂ = 150 × 2

T₂ = 300 K

Finally, we shall convert 300 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 300 K

T(°C) = 300 – 273

T(°C) = 27°C

Thus, the final temperature is 27°C

6 0
3 years ago
If a total force exerted by water in a container with a bottom area of 2 square meters is 450 newtons, what's the water pressure
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mylen [45]

The distance covered by the acorn is 3.136 m.

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The time taken for the acorn to hit the ground is 0.8 s. As it is a free fall, the acorn will be completely under the influence of gravity. So the acceleration will be acceleration due to gravity.

Then using the second law of equation,

s=ut+\frac{1}{2}gt^{2}

Since the initial velocity and time is zero, then the time taken to reach the ground is stated as 0.8 s, so

   s=0+\left(\frac{1}{2} \times 9.8 \times 0.8 \times 0.8\right)=\frac{6.272}{2}=3.136 \mathrm{m}

So the distance covered by the acorn is 3.136 m.

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