Answer:
181.48 N
Explanation:
Calculate the area :
Area = pi * r² ;
pi = 3.14 ; r1 = 90cm /100 = 0.9m ; r2 = 10/100 = 0.1m
Area 1, A1 = 3.14 * 0.1² = 0.0314 m²
Area 2, A2 = 3.14 * 0.9² = 2.5434 m²
Force, F = mass * acceleration due to gravity
F2 = 1500 * 9.8 = 14700 N
Force 1 / Area 1 = Force 2 / Area 2
Force 1 = (Force 2 / Area 2), * Area 1
Force 1 = (14700 / 2.5434) * 0.0314
Force = 5779.6650 * 0.0314
= 181.48 N
Explanation:
13 cmHg (centimeters of mercury) is the pressure at the bottom of a column of mercury 13 cm deep. It is the equivalent of about 17.3 kPa or 2.5 psi.
One of the main uses of this device is to test a beam of charged particles
What is cathode ray tube?
The cathode ray tube determines the charge flowing in a gas. When an electric field is set up using metal electrodes, the cathode ray tends to bend towards the positive electrode.
This concludes that a charge and the electrodes present helps determine the charge of the beam of charged particle.
Thus, one of the main uses of this device is to test a beam of charged particles.
Learn more about cathode ray tube.
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Answer:
magnitude of net magnetic field at given point is

Explanation:
As we know that magnetic field due to a long current carrying wire is given as

here we we will find the magnetic field due to wire which is along x axis is given as

r = 2 m
now we have

into the plane
Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as

r = 2 m
now we have

along + x direction
Since the two magnetic field is perpendicular to each other
So here net magnetic field is given as

