The correct answer is alpha
        
                    
             
        
        
        
Answer:
The smallest distance the student that the student could be possibly be from the starting point is 6.5 meters. 
Explanation:
For 2 quantities A and B represented as 
 and
 and 
The sum is represented as 
 
 
 For the the values given to us the sum is calculated as

 
 
Now the since the uncertainity inthe sum is 
The closest possible distance at which the student can be is obtained by taking the negative sign in the uncertainity
Thus closest distance equals  meters
meters 
 
        
             
        
        
        
Answer:
The diameter is EF
Explanation:
Given
Circle A (See attachment)
Required
Determine the line that represents the diameter
First, it should be noted that the diameter of a circle is always a straight line.
From the attachment, the circle has the following straight lines:
It should also be noted that the diameter passes through the center of a circle and divides it into two congruent parts.
From the list of straight lines above, only line EF satisfy this property
Hence, the diameter of the circle is line EF.
 
        
                    
             
        
        
        
Answer:
 24kgm/s
Explanation:
Given parameters: 
Force  = 80N 
Mass of object  = 6kg 
Initial velocity  = 4m/s 
Final velocity = 8m/s 
Solution: 
Impulse  = ? 
Solution: 
The impulse on a body is its change in momentum. 
     Impulse  = m (v  - u )
m is the mass
v is the final velocity 
u is the initial velocity 
   Now insert the parameters and solve; 
           Impulse  = 6 (8 - 4) = 24kgm/s
 
        
             
        
        
        
Answer:
Orbital Eccentricity
Planet	Orbital Eccentricity	
(Point in Orbit Closest to Sun)
measured in AU's
Mercury	0.206	
Venus	0.007	
Earth	0.017	
Mars	0.093	
Jupiter	0.048	
Saturn	0.056	
Uranus	0.047	
Neptune	0.009	
Pluto	0.248	
Explanation:
link to information:
https://www.enchantedlearning.com/subjects/astronomy/glossary/Eccentricity.shtml