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olga_2 [115]
3 years ago
10

The measure of a spring’s resistance to being compressed or stretched is the

Physics
2 answers:
larisa86 [58]3 years ago
7 0

<u>Answer;</u>

<em>Spring constant </em>

<u>Explanation;</u>

The measure of a spring’s resistance to being compressed or stretched is the <u>spring constant</u>.

  • The symbol of spring constant is K, since it is a constant. From the Hooke's law,for a helical spring or any elastic material, the extension force is directly proportional to the extension provided the elastic limit is not exceeded.
  • Therefore; the spring constant = Force/extension. That is; K = F/e; where k is the spring constant, F is the extension force and e is the extension.
  • Spring constant depicts the resistance of the spring to compressional and stretching forces.
WINSTONCH [101]3 years ago
3 0

Answer: Spring constant

Explanation:

The stiffness of the spring is determined by its spring constant. It measured in Newtons per meter (N/m).

The spring resists change in its length- either being extended or compressed. It always tends to come back to its original position.

<u>Hooke's law </u>states that force F required to extend or compress a spring is directly proportional to its displacement x.

F ∝ x

F = k x

where, k is the spring constant.

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How can a 1kg ball have more kinetic energy than a 100kg ball? Explain both using words and by providing a numerical example
MariettaO [177]

1 kg ball can have more kinetic energy than a 100 kg ball as increase in velocity is having greater impact on K.E than increase in mass.

<u>Explanation</u>:

We know kinetic energy can be judged or calculated by two parameters only which is mass and velocity. As kinetic energy is directly proportional to the (velocity)^2 and increase in velocity leads to greater effect on translational Kinetic Energy. Here formula of Kinetic Energy suggests that doubling the mass will double its K.E but doubling velocity will quadruple its velocity:

\text { Kinetic Energy }=\frac{1}{2} m v^{2}

Better understood from numerical example as given:

If a man A having weight 50 kg run with speed 5 m/s and another man B having 100 kg weight run with 2.5 m / s. Which man will have more K.E?

This can be solved as follows:

\text { Kinetic Energy of } \mathrm{A}=\frac{1}{2} 50 \times 5^{2}=625 \mathrm{J}

\text { Kinetic Energy bf } \mathrm{B}=\frac{1}{2} 100 \times 2.5^{2}=312.5 \mathrm{J}

It shows that man A will have more K.E.

Hence 1 kg ball can have more K.E than 100 kg ball by doubling velocity.

4 0
3 years ago
when do you use cos and sin in situations like these? is horizontal always cos and vertical always sin?
Andreas93 [3]

Answer:

yes

Explanation:

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