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Serhud [2]
4 years ago
10

A lever is placed on a fulcrum. A rock is placed on the right end of the lever and a downward (counterclockwise) force is applie

d to the left end of the lever. What measurements would be most effective to help you determine the angular momentum of the system? (Assume the lever itself has negligible mass.)
Physics
1 answer:
DIA [1.3K]4 years ago
7 0

Answer:

measurements that would be most effective to help you determine the angular momentum of the system are

the mass of the rock, the length of the lever on both sides of the fulcrum, and the force applied on the right side of the lever

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3 years ago
A ball is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa
vovangra [49]

Answer:

a) 48.5 ft/s

b) 36.5 ft

c) -80.3 ft/s

Explanation:

a)

The equation of motion of the ball is :

y(t) = -16.1 ft/s^2 * t^2 + Vo*t

Where Vo is the initial velocity

If y(5s) = - 160 ft:

-160 ft = -16.1 ft/s^2 * (5 s)^2 + Vo*(5s)

Solving for Vo

Vo  = (16.1*25- 160) ft / 5s = 48.5 ft/s

b)

To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.

v(t) = -32.2 ft/s^2 * t + Vo

t = Vo/32.2ft/s^2 = 1.5 s

And now, the highest point which the ball reached is given by:

y(1.5s) = -16.1 ft/s^2 * (1.5)^2 + Vo*(1.5s)

y(1.5s) = 36.52 ft

c)

We now need the time at which y(t') = -64 ft

-64 = -16.1*t'^2 + 48.5*t'

By means of the quadratic formula, we find that

t' = 4.00498 s ≈ 4 s

And the velocity at t = 4s is:

v(4s) = -32.2 ft/s^2 * 4s +48.5 ft/s = -80.3 ft/s

3 0
4 years ago
If kinetic energy of a body of mass 10 kg is 2000 J find velocity ​
weqwewe [10]

Answer:

I guess answer is 10m/s.

Explanation:

Kinetic Energy=1/2 mv^2

or,2000J=1/2×10kg×v^2

or2000J=5kg.v^2

or,2000J/5kg=v^2

or,100J/kg=v^2

or,v=10m/s

6 0
2 years ago
A ball is thro.d hit the grouvelocity)?
kati45 [8]

Answer:

The velocity of the ball is 3.52 m/s.

Explanation:

A projectile is any object that moves under the influence of gravity and momentum only. Examples are; a thrown ball, a fired bullet, a kicked ball, thrown javelin, etc.

Given that the ball was thrown vertically upward on the top of a skyscraper of  height 61.9 m. So that the velocity can be determined by;

      u = \sqrt{\frac{2H}{g} }

Where: u is the velocity of the object, H is the height and g is the gravitational force on the object. Given that: H = 61.9 m and g = 10 m/s^{2}, then;

 u = \sqrt{\frac{2*61.9}{10} }

   = \sqrt{\frac{123.8}{10} }

u  = 3.5185

The velocity of the ball is 3.52 m/s.

3 0
4 years ago
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