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Serhud [2]
3 years ago
10

A lever is placed on a fulcrum. A rock is placed on the right end of the lever and a downward (counterclockwise) force is applie

d to the left end of the lever. What measurements would be most effective to help you determine the angular momentum of the system? (Assume the lever itself has negligible mass.)
Physics
1 answer:
DIA [1.3K]3 years ago
7 0

Answer:

measurements that would be most effective to help you determine the angular momentum of the system are

the mass of the rock, the length of the lever on both sides of the fulcrum, and the force applied on the right side of the lever

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A 45 N girl sits on a bench 0.6 meters off the ground. How much work is done on the bench?
ycow [4]

Answer: 27 joules

Explanation:

Work is done when force is applied on the bench over a distance. it is measured in joules.

Workdone = force x distance

= 45 N x 0.6 metres

= 27 joules

Thus, 27 joules of work is done on the bench.

6 0
3 years ago
If a ball with an original velocity of zero is dropped from a tall structure and it takes 7 seconds to hit the ground, what velo
Colt1911 [192]
The velocity of the ball when it reaches the ground is equal to B. 68.6 m/s. This value was obtained from the formula Vf = Vi + at. Vf is the final velocity. Vi is the initial velocity. The acceleration is "a", while the time of travel is "t". The solution is:

<span>Vf = Vi + at
</span>Vf = 0 + (-9.8 m/s^2) (7 s)
Vf = -68.6 m/s

The negative sign denotes the direction of the ball.
5 0
3 years ago
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10 POINTS AND BRAINLIEST!!!!
Maurinko [17]
The answer is earth.
7 0
3 years ago
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A sports car skids off of a wet mountain road at 48.5 m/s and lands in the river, 110
Oxana [17]

Answer:

  about 4.74 seconds

Explanation:

The time to fall distance d from height h is given by ...

  t = √(2d/g)

  t = √(2·110 m/(9.8 m/s^2)) ≈ 4.74 s

It will take the car about 4.74 seconds to fall 110 meters to the river.

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We assume the car's speed is horizontal, so does not add or subtract anything to/from the time to fall from the height.

3 0
2 years ago
Block B has mass 6.00 kg and sits at rest on a horizontal, frictionless surface. Block A has mass 2.50 kg and sits at rest on to
zzz [600]

Answer:

Explanation:

Block A sits on block B and force is applied on block A . Block A will experience two forces 1) force P and 2 )  friction force in opposite direction of motion . Block B will experience one force that is force of friction in the direction of motion .

Let force on block A be P . friction force on it will be equal to kinetic friction, that is μ mg , where μ is coefficient of friction and m is mass of block A

friction force = .4 x 2.5 x 9.8

= 9.8 N

net force on block A = P - 9.8

acceleration = ( P - 9.8 ) / 2.5

force on block B = 9.8

acceleration = force / mass

= 9.8 / 6

for common acceleration

( P - 9.8 ) / 2.5  = 9.8 / 6

( P - 9.8 ) / 2.5 = 1.63333

P = 13.88 N .

4 0
3 years ago
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