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3 years ago

What changes depending on location in the universe, mass or weight. Explain

Physics

2 answers:

valentinak56 [21]3 years ago

7 0

Answer:

Weight

Explanation:

The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass. The amount of matter in a material is a characteristic of a given object. But, the force of gravity that acts upon the object's mass depends of where the object is placed. For example, placed on Earth, some force is corroborated, but on the Moon, the force of gravity would be different because Moon has a different acceleration of gravity.

Black_prince [1.1K]3 years ago

3 0

Weight changes. Mass should remain the same. Weight is the effect of mass in a gravity field, so on Earth, you'll with 180 pounds, but on the moon, only 30 - while your mass remains the same in both places.

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Inceptual Physics - Wavos Test - Semester 1 - 2021

Dvinal [7]

Answer:

A thats answer thankyou

4 0

2 years ago

what is the geocentric model of stars and planets? a.) the belief that stars and planets revolve around the earth b.) the belief

amid [387]

a.) the belief that stars and planets revolve around the earth

Explanation:

The geocentric model of stars and planets is the belief that stars and planets revolves around the earth.

The model places the earth at the center of the system.

Geo - earth ; centric - center
This was the original school of thought about the way the earth relates to other bodies in the universe.
This model was replaced by the heliocentric universe in which stars are at the center and the planets revolves round them.
The idea was put forward by Nicola Copernicus

learn more:

Energy of the sun brainly.com/question/1140127

#learnwithBrainly

7 0

3 years ago

A rope is vibrating so as to form the standing wave pattern shown. How many antinodes are present in the rope?a- 5b- 4c- 8d- 10e

denpristay [2]

c) 8

Explanation

When you shake a rope, the particles in the rope move up and down, and the wave moves forward or away from the source of energy. The rope moves in a direction that is perpendicular

Nodes are the places where the rope doesn't move at all; antinodes occur where the motion is greatest.

Step 1

let's check the graph:

a) Nodes

and Antinodes

so, in the ripe there are 8 antinodes

therefore, the answer is

c) 8

4 0

1 year ago

A ball is dropped from the top of a cliff. By the time it reaches the ground, all of its gravitational potential energy has been

Katena32 [7]

Answer:

20 m

Explanation:

Initial potential energy = final kinetic energy

mgh = 1/2 mv²

gh = 1/2 v²

h = v² / (2g)

Given v = 20 m/s and g = 10 m/s²:

h = (20 m/s)² / (2 × 10 m/s²)

h = 20 m

4 0

3 years ago

The initial temperature of 150 g of ice is ????20°C. The spe- cific heat capacity of ice is 0.5 cal/g·C° and water’s is 1 cal/g·

soldier1979 [14.2K]

1. 13,500 cal

First of all, we need to find the amount of heat needed to raise the temperature of the ice from -20°C to 0°C. This is given by

$Q_1 = m C_i \Delta T$

where

m = 150 g is the mass of the ice

C_i = 0.5 cal/g·C° is the specific heat capacity of the ice

$\Delta T=0 C-(-20 C)=20^{\circ}C$ is the change in temperature of the ice

Substituting,

$Q_1 = (150 g)(0.5 cal/gC)(20 C)=1500 cal$

Now we have to find the amount of heat needed to melt the ice, which is

$Q_2 = m \lambda_f$

where

m = 150 g is the mass of the ice

$\lambda_f = 80 cal/g$ is the latent heat of fusion

Substituting,

$Q_2 = (150 g)(80 cal/g)=12,000 cal$

So the total heat required is

$Q_3 = 1500 cal + 12,000 cal = 13,500 cal$

2. 3750 cal

The additional amount of heat required to heat the water to 25°C is

$Q_4 = m C_w \Delta T$

where

m = 150 g is the mass of water

C_w = 1 cal/g·C is the speficic heat capacity of water

$\Delta T=25 C-0 C=25^{\circ}C$ is the change in temperature

Substituting,

$Q_4 = (150 g)(1 cal/gC)(25 C)=3,750 cal$

3. 9200 cal

First of all, we need to find the amount of heat needed to raise the temperature of the ice from -20°C to 0°C. As at point 1., this is given by

$Q_1 = m C_i \Delta T$

where

m = 80 g is the mass of the ice

C_i = 0.5 cal/g·C° is the specific heat capacity of the ice

$\Delta T=0 C-(-20 C)=20^{\circ}C$ is the change in temperature of the ice

Substituting,

$Q_1 = (80 g)(0.5 cal/gC)(20 C)=800 cal$

Now we have to find the amount of heat needed to melt the ice:

$Q_2 = m \lambda_f$

where

m = 80 g is the mass of the ice

$\lambda_f = 80 cal/g$ is the latent heat of fusion

Substituting,

$Q_2 = (80 g)(80 cal/g)=6,400 cal$

Finally, the amount of heat required to heat the water to 25°C is

$Q_3 = m C_w \Delta T$

where

m = 80 g is the mass of water

C_w = 1 cal/g·C is the speficic heat capacity of water

$\Delta T=25 C-0 C=25^{\circ}C$ is the change in temperature

Substituting,

$Q_3 = (80 g)(1 cal/gC)(25 C)=2,000 cal$

So the total heat required is

$Q=Q_1+Q_2+Q_3=800 cal+6,400 cal+2,000 cal=9,200 cal$

4. No

Explanation:

The total heat required for this process consists of 3 different amounts of heat:

1- The heat required to bring the ice at melting temperature

2- The heat required to melt the ice, while its temperature stays constant

3- The heat required to raise the temperature of the water

However, computing how much heat is required to melt the ice and adding the amount of heat required to raise the temperature of 80 g of water by 45°C is not equivalent: in fact, the calculation of point 1) requires to use the specific heat capacity of ice, not that of water, therefore the two are not equivalent.

4 0

3 years ago