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4 years ago

What changes depending on location in the universe, mass or weight. Explain

Physics

2 answers:

valentinak56 [21]4 years ago

7 0

Answer:

Weight

Explanation:

The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass. The amount of matter in a material is a characteristic of a given object. But, the force of gravity that acts upon the object's mass depends of where the object is placed. For example, placed on Earth, some force is corroborated, but on the Moon, the force of gravity would be different because Moon has a different acceleration of gravity.

Black_prince [1.1K]4 years ago

3 0

Weight changes. Mass should remain the same. Weight is the effect of mass in a gravity field, so on Earth, you'll with 180 pounds, but on the moon, only 30 - while your mass remains the same in both places.

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A 15-ft ladder rests against a vertical wall. if the top of the ladder slides down the wall at a rate of 0.33 ft/sec, how fast,

aivan3 [116]

Let the corner of the wall and floor is our origin

Now the end of the ladder is on the floor is at distance x and top end on the wall is at distance y from this corner.

So we will use Pythagoras Theorem to find the length of the ladder.

$x^2 + y^2 = L^2$

now if we differentiate whole equation with time

$2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0$

now the speed of the end of the ladder at the end of the floor will be given as

$\frac{dx}{dt} = -\frac{y}{x} \frac{dy}{dt}$

here $\frac{dy}{dt}$ is the speed of end of the ladder on the wall.

so here we also know that

$9^2 + y^2 = 15^2$

$y = 12 ft$

now we will plug in all values in the equation

$\frac{dx}{dt} = \frac{12}{9}*(0.33)ft/s$

$v = 0.44 ft/s$

so the end of the ladder on the floor will move with speed v = 0.44 ft/s

4 0

3 years ago

A bus travelling 30.0 km/h east has a constant increase in speed of 1.5 m/s. What is its velocity 6.8s later

alekssr [168]

Answer:

8.72 seconds before

Explanation:

and 27.1 secs after

7 0

3 years ago

A point charge is placed 3m from a 4uc charge what is the strength of the electric field on the point charge at this distance ro

Vlada [557]

The strength of the electric field on the point charge at this distance will be 4000 V/m.

<h3>What is the strength of the electric field?</h3>

The strength of the electric field is the ratio of electric force per unit charge.

The given data in the problem is;

Qis the unit charge = 4.0 × 10⁻⁶ C

E is the strength of the electric field

R is the distance from point charge = 3 m

The strength of the electric field is;

$\rm E = \frac{KQ}{R^2} \\\\ \rm E = \frac{9 \times 10^9 \times 4 \times 10^{-6} \ C}{3^2} \\\\ E= 4000 V/m$

Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.

To learn more about the strength of the electric field refer to the link;

brainly.com/question/15170044

#SPJ1

7 0

2 years ago

a fixed amount of ideal gas is held in a rigid container that expands negligibly when heated. at 20 the gas pressure is p. if we

pantera1 [17]

Answer:

When the temperature of the gas is increased from 20 to 40, the pressure will be 2p

Explanation:

Given;

initial temperature of the gas, T₁ = 20 K

final temperature of the gas, T₂ = 40 k

initial pressure of the gas, P₁ = P

final pressure of the gas, P₂ = ?

Apply pressure law of gases;

$\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\P_2 = \frac{P_1T_2}{T_1} \\\\P_2 = \frac{40P}{20} \\\\P_2 = 2P$

Therefore, when the temperature of the gas is increased from 20 to 40, the pressure will be 2p

5 0

3 years ago

The motion of an object undergoing constant acceleration can be modeled by the kinematic equations. One such equation is xf=xi+v

Mademuasel [1]

Answer:

a = -04978 m / s²

Explanation:

For this exercise we can use the kinematics equations, as the initial speed, distance and time indicate, we can use

x = x₀ + v₀ t + 1 /2 a t²

½ a t² = x-x₀ - v₀ t

a = (x-x₀ - v₀ t) 2 / t²

let's reduce the magnitudes to the SI system

x₀ = 1000 mm = 1 m

x = 5000mm = 5m

let's calculate

a = (5 - 1 - 15 60) 2/60²

a = -04978 m / s²

negative sign indicates that braking is related

7 0

3 years ago