1/6x = 2.....multiply both sides by the reciprocal 6/1
(6/1)(1/6)x = 2(6/1)
1x or just x = 12
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
They are quadrilaterals that have opposite sides equal in length.
Answer:
Expected value would be $ 0.896
Step-by-step explanation:
Given,
The price of the lottery ticket = $44800000,
Also, the probability of winning the grand prize = .000000020,
Thus, the expected value of the lottery ticket = value of the lottery ticket × probability of getting the lottery ticket
= 44800000 × .000000020
= $0.896
Note : value of lottery ticket = prize amount - cost of each ticket,
Here the cost price of a ticket is not given,
That's why we did not consider it.
Answer:
c
Step-by-step explanation:
