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natka813 [3]
3 years ago
14

Sawarasenikimiwa⛓shoujonano?✨böKùWâ‍♀️ÿARiçHiñBįCChĪńOoSû‍♀️DàYO

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
7 0

Answer:

wat language is this?? or is it even a thing im

confused

LiRa [457]3 years ago
3 0

Step-by-step explanation:

What? I don't understand this language and thnx for free points

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What is the product 3x5(2x2+4x+1)
lesya692 [45]

Answer:

6x^7+12x^6+3x^5

Step-by-step explanation:

The given expression is:

3x^5(2x^2+4x+1)

We expand the parenthesis using the distributive property to obtain;

3x^5(2x^2)+3x^5(4x)+3x^5(1)

Recall that;

a^m\imes a^n=a^{m+n}

We apply this property and multiply out the constant terms to obtain;

6x^7+12x^6+3x^5

3 0
3 years ago
Macy is painting a design that contains two repeating patterns. One pattern repeats every 8 inches. The other repeats every 12 i
Firlakuza [10]
The pattern will be at the same place at 2 feet, 4 feet, 6 feet, 8 feet, 10 feet, 12 feet, 14 feet, 16 feet, and 18 feet
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3 years ago
What the answer to <br>-2v+8 (1+2v)=-90
dexar [7]

Answer:

v=2-2root7, v=2+2root7  

Step-by-step explanation:

-2v+8(1+2v)=-90

-2-4v^2+8+16v=-90

6-4v^2+16v=-90

-4v^2+16v=-96

v=2-2root7, v=2+2root7

4 0
3 years ago
Read 2 more answers
2. Calculate the energy in joules of a photon whose frequency is 7.55×1014 Hz.
igomit [66]
The energy of a photon is given by
E = h × v

where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴

Substitute 'h' and 'v' into the formula we have

E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
8 0
3 years ago
The Adventures of Huckleberry Finn, written by Mark Twain, has an ISBN of 978-014243717a, where a is the check number. What is t
Simora [160]

Answer: D. 9

Step-by-step explanation:

4 0
3 years ago
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