Given:
Temperature = T, unknown
Saturated Solution, NH4Cl concentration = 60g/100g H2O = 0.6g NH4Cl/g H2O
Assume density of H2O = 1 g/ml
m = 0.6g NH4Cl/g H2O / 1 g/ml
m = 0.6g NH4Cl/ml
See the table of saturated solutions and identify the temperature at which the concentration of NH4Cl is 60g/100g H2O. <span />
<u>Answer:</u> The value of is 0.136 and is reactant favored.
<u>Explanation:</u>
Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
For the chemical reaction between carbon monoxide and hydrogen follows the equation:
The expression for the is given as:
We are given:
Putting values in above equation, we get:
There are 3 conditions:
- When ; the reaction is product favored.
- When ; the reaction is reactant favored.
- When ; the reaction is in equilibrium.
For the given reaction, the value of is less than 1. Thus, the reaction is reactant favored.
Hence, the value of is 0.136 and is reactant favored.
Answer : The symbol of the element is Selenium (Se).
Explanation :
Electronic configuration is distribution of electrons in an atom in atomic orbitals.
The electronic configuration of [Kr] =
Total number of electrons in [Kr] = 36
Due to -2 charge, 2 electrons are withdrawn from the electronic configuration of [Kr].
Now the total number of electrons left = 36 - 2 = 34
And the Selenium[Se] is the element which has 34 number of electrons.
Electronic configuration of [Se] =
Answer:
Vinegar
Explanation:
Both sodium citrate and glucose are polar substances. Since they are polar substances, they will be found in greater concentration in the aqueous phase. The aqueous phase in this case is vinegar.
Hence a greater concentration of the sodium citrate and glucose will be found in the vinegar with only very little concentration in the oil.
Answer: 0.0 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of butane
b) moles of oxygen
According to stoichiometry :
2 moles of butane require 13 moles of
Thus 0.09 moles of butane will require = of
Butane is the limiting reagent as it limits the formation of product and oxygen is present in excess as (1.02-0.585)=0.435 moles will be left.
Thus all the butane will be consumed and 0.0 grams of butane will be left.