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Westkost [7]
3 years ago
10

Please help me i will give brain list​

Chemistry
2 answers:
sesenic [268]3 years ago
7 0

Answer:

a. pentane = C5H12

b. Heptane = C7H16

c. Hexyne = C6H10

d. Octene = C8H16

e. Nonane = C9H20

Hope it helps.

labwork [276]3 years ago
5 0

1-pentene

Molecular Formula C5H10

Condensed Structural FormulaCH2=CH(CH2)2CH3

Melting Point (°C)–138

Boiling Point (°C)30

2- heptane is the straight-chain alkane with the chemical formula H3C(CH2)5CH3 or C7H16, and is one of the main components of gasoline (petrol).

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The HF bond length is 92 pm, 16% shorter than the sum of the covalent radii of H (37 pm) and F (72 pm). Suggest a reason for thi
Elza [17]

Due to electronegativity difference between H and F atom.

<h3>What is the reason for the difference ?</h3>
  • The bond length of HF is 92 pm. It is 16% shorter than the sum of the covalent radii of H (37 pm) and F (72 pm).
  • The shorter of the bond length is due to the difference in electronegativity between H and F atom. The electronegativity of F is 4.0, whereas the electronegativity of H is 2.1.
  • Greater the difference of electronegativity between the bonded atoms, shorter will be the bond length.
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Thus from the above conclusion we can say the difference in electronegativity between H and F atom this is the reason for shorter bond length of HF.

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3 0
1 year ago
Base your answers to questions 74 through 76 on the data table below and on your knowledge of Earth
Serjik [45]

Answer:

See explanation

Explanation:

Now we have, the graph attached.the stable disintegration product of C-14 is N-14.

Then;

Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;

N/No = (1/2)^t/t1/2

N = mass of C-14  at time t

No= mass C-14 originally present

t = time taken for  N amount of C-14 to remain

No = mass of C-14 originally present

t1/2 = half life of C-14

N/64 = (1/2)^17,100/5730

N/64 = (1/2)^3

N/64 = 1/8

8N = 64

N = 8 g

Download xlsx
6 0
3 years ago
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