1.1214 mL will a 0.205-mole sample of He occupy at 3.00 atm and 200 K.
<h3>What is an ideal gas equation?</h3>
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Using equation PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= 3.00 atm
V= ?
n=0.205 mole
R= ![0.082057338 \;L \;atm \;K^{-1}mol^{-1}](https://tex.z-dn.net/?f=0.082057338%20%5C%3BL%20%5C%3Batm%20%5C%3BK%5E%7B-1%7Dmol%5E%7B-1%7D)
T=200 K
Putting value in the given equation:
![\frac{nRT}{P} =V](https://tex.z-dn.net/?f=%5Cfrac%7BnRT%7D%7BP%7D%20%3DV)
![V= \frac{0.205 \;mole\;0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 200}{3 \;atm}](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B0.205%20%5C%3Bmole%5C%3B0.082057338%20%5C%3BL%20%5C%3Batm%20%5C%3BK%5E%7B-1%7Dmol%5E%7B-1%7D%20X%20200%7D%7B3%20%5C%3Batm%7D)
V= 1.1214 mL
Learn more about the ideal gas here:
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Answer:
(C) H3O+(aq) + C2H3O2−(aq) -> HC2H3O2(aq) + H2O(l)
Explanation:
A buffer is a solution of a weak acid and its salt. It mitigates against changes in acidity or alkalinity of a system. A buffer maintains the pH at a constant value by switching the equilibrium concentration of the conjugate acid or conjugate base respectively.
Addition if an acid shifts the equilibrium position towards the conjugate acid side while addition of a base shifts the equilibrium position towards the conjugate base side.
Answer:
it says select all that apply hhh easy just select and apply the answer hhh
Explanation:
Answer:
<h2>10 m/s</h2>
Explanation:
Her average speed can be found by using the formula
![v = \frac{d}{t} \\](https://tex.z-dn.net/?f=v%20%3D%20%20%5Cfrac%7Bd%7D%7Bt%7D%20%20%5C%5C%20)
d is the distance
t is the time taken
From the question we have
![v = \frac{300}{30} = 10 \\](https://tex.z-dn.net/?f=v%20%3D%20%20%5Cfrac%7B300%7D%7B30%7D%20%20%3D%2010%20%5C%5C%20)
We have the final answer as
<h3>10 m/s</h3>
Hope this helps you