<em>What volume do 5 moles of a gas occupy at 28 ° C and 3 atm of pressure?</em>
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<h3>Further explanation</h3>In general, the gas equation can be written
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
n= 5 moles
T=28 +273=301 K
P=3 atm
The volume of the gas :
Explanation:
Given parameters:
Dimension = 8.5in²
we are to convert from in² to cm²
in² = in x in
cm² = cm x cm
1 in = 2.54cm
Using dimensional analysis;
8.5in² x
= 54.84cm²
We solved this problem using dimensional analysis where we multiplied the unit with 1.
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Considering the ideal gas law, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.
<h3>Definition of ideal gas</h3>
An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
<h3>Ideal gas law</h3>An ideal gas is characterized by absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:
P×V = n×R×T
<h3>Volume of gas</h3>In this case, you know:
Replacing in the ideal gas law:
1.50 atm×V = 11.36 moles×0.082 × 298 K
Solving:
V= (11.36 moles×0.082 × 298 K) ÷ 1.50 atm
<u><em>V= 184.899 L</em></u>
Finally, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.
Learn more about the ideal gas law: