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dalvyx [7]
3 years ago
11

Given that a 3cm lenght of magnesium weights approximately 0.04g, calculate the number of moles of acid that reacted with the 9c

m piece of magnesium ribbon.​
Chemistry
1 answer:
pychu [463]3 years ago
7 0
Iiiiiiiiiiiiooooooopp.
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Pls help . I don't know this one .
aliya0001 [1]
The answer is the first one, Xe
5 0
3 years ago
In a reaction of a potential new fuel, it is found that when 2.81 moles of the fuel combusts, 1,612 kJ of energy is released. Wh
Tema [17]

Answer:

-573.67

Explanation:

whenever energy is released in a chemical reaction, we would then expect the delta H of the reaction to be negative because the reaction is an exothermic reaction.

now we have that 2.81 moles of fuel when it combusts would releases 1612kJ of energy

thus, 1 mole will release 1612/2.81 = -573.67kJ of heat

Therefore the delta H of the reaction = -573.67 kJ/mol

3 0
2 years ago
Identify which sets of Quantum Numbers are valid for an electron. Each set is ordered (n,ℓ,mℓ,ms).
skad [1K]

3,2,0,1/2

1,0,0,1/2

3,2,2,1/2

4,2,1,1/2

2,1,-1,-1/2

THEY ARE VALID


3 0
3 years ago
What is scientific "law"?
Natalka [10]
Based on (repeated) experiments or observations, that describe or predict a range of natural phenomena. the answer is c (sorry if i’m incorrect)
4 0
3 years ago
A tank of gas is found to exert 8.6 atm at 38°C. What would be the required
Vesna [10]

Answer:

36.2 K

Explanation:

Step 1: Given data

  • Initial pressure of the gas (P₁): 8.6 atm
  • Initial temperature of the gas (T₁): 38°C
  • Final pressure of the gas (P₂): 1.0 atm (standard pressure)
  • Final temperature of the gas (T₂): ?

Step 2: Convert T₁ to Kelvin

We will use the following expression.

K = °C +273.15

K = 38 °C +273.15 = 311 K

Step 3: Calculate T₂

We will use Gay Lussac's law.

P₁/T₁ = P₂/T₂

T₂ = P₂ × T₁/P₁

T₂ = 1.0 atm × 311 K/8.6 atm = 36.2 K

6 0
2 years ago
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